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Ket [755]
2 years ago
8

Find the equation of the line in slope intercept form

Mathematics
2 answers:
Ann [662]2 years ago
4 0

Answer:

y = 1/3x - 3

Step-by-step explanation:

First, find the slope

(3, -2)

(0, -3)

-2-(-3) = 1

3 - 0 = 3

Slope = 1/3

Now, find the y intercept

y = mx + b

-2 = 3 * 1/3 + b

-2 = 1 + b

-3 = b

Rewrite the equation

y = 1/3x - 3

Please let me know if I did something wrong!

Jlenok [28]2 years ago
3 0

Answer:

y= 1/3x-3

Step-by-step explanation:

rise /run

-3 is the point you start

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Anyone help?<br><br> What is the derivative of x^2 + 2x - 4?<br><br> Thanks!
castortr0y [4]
Let's take the derivative of each term one by 1

x^2
Apply the power rule for derivatives.
2x^(2-1) = 2x
You get 2x.

2x
Apply the power rule (x^1) and the constant multiple rule.
2 * x^(1-1) = 2 * x^0 = 2
You get 2.

-4
The derivative of a constant is 0.

Put that together and you get 2x + 2

Have an awesome day! :)
4 0
3 years ago
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My key can’t perform this but I can solve it on a sheet...
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7 0
2 years ago
HELP ME PLEASE !!!!!!!!
fredd [130]

Answer:

AB = 14

DE =7

Step-by-step explanation:

Remark

<em>AB</em>

Opposite sides of a parallelogram are equal.

AB = CD

AB = 14

<em>DE</em>

According to the diagram AE = 19

AD = 26 which is the same size as BC

DE = 26 - 19 = 7

DE = 7

4 0
3 years ago
Subtract (x^2+3x-4) -(4x-2x^2-3)
Feliz [49]

Answer:

3 x^2 - x + -1

Step-by-step explanation:

Simplify the following:

-(4 x - 2 x^2 - 3) + x^2 + 3 x - 4

Factor -1 out of -2 x^2 + 4 x - 3:

--(2 x^2 - 4 x + 3) + x^2 + 3 x - 4

(-1)^2 = 1:

2 x^2 - 4 x + 3 + x^2 + 3 x - 4

Grouping like terms, 2 x^2 + x^2 + 3 x - 4 x - 4 + 3 = (x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3):

(x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3)

x^2 + 2 x^2 = 3 x^2:

3 x^2 + (3 x - 4 x) + (-4 + 3)

3 x - 4 x = -x:

3 x^2 + -x + (-4 + 3)

3 - 4 = -1:

Answer: 3 x^2 - x + -1

4 0
3 years ago
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