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3 years ago

Can sb help me it’s due soon

Mathematics

1 answer:

harina [27]3 years ago

7 0

Answer:

I think 84 but you may need to check just to be sure :)

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Which Kind of Triangle is Shown?

Alexus [3.1K]

Hi! The answer is right scalene triangle! Hope this is right! :)

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2 years ago

Just a tad bit more points :)

swat32

Answer:

Thx have a great day :)

Step-by-step explanation:

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3 years ago

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A basketball coach has a bag containing 2 red, 5 orange, and 3 brown basketballs. The coach takes 2 basketballs from the bag for

Ronch [10]

Answer:

30%

Step-by-step explanation:

You add the total number of balls, which is 10. and then it is asking for brown balls and looking at the equation you know there are 3. so 3/10 is .30 which is 30%

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3 years ago

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Find the area of each figure below

Ugo [173]

Answer:

25. $27a^{3}b^{2}$

26. $3\pi x^{3}y$

Step-by-step explanation:

For 25:

$A = \frac{a+b}{2} h$ (area of a trapezoid)

$A=\frac{11a^{2}b+7a^{2}b}{2} *3ab$ (substitute terms)

$= \frac{18a^{2}b}{2}*3ab$ (collect like terms)

$= 9a^{2}b*3ab$ (reduce the fraction by crossing out 2)

$= 27a^{3}b^{2}$ (calculate)

For 26:

$A=\pi r^{2}$ (equation of area of a circle)

$A=\pi (3x^{3} y)^{2}$ (enter the radius)

$= 3\pi x^{3} y$ (communtative property to reorder the terms)

7 0

3 years ago

NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0

3 years ago