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Elenna [48]
3 years ago
14

4(5x-2)=2(9x+3) help please! 12 points and brainliest

Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer:

x = 7

Step-by-step explanation:

Given

4(5x - 2) = 2(9x + 3) ← distribute parenthesis on both sides

20x - 8 = 18x + 6 ( subtract 18x from both sides )

2x - 8 = 6 ( add 8 to both sides )

2x = 14 ( divide both sides by 2 )

x = 7

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Find the values of each variables in each quadrilateral. ​
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the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function
Likurg_2 [28]

The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about area here:

brainly.com/question/27683633

#SPJ4

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Please help me with this urgent
erma4kov [3.2K]
1 is b and it would be 164
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