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Aliun [14]
3 years ago
8

Hi I am in desperate need of a "tutor" If anyone is decent at Algebra II, any little help is welcomed! Please respond to this an

d I will message you on here. I will explain my situation through there
I am honestly in a really tight spot in school and I really need some assistance with my work, thanks :)
Mathematics
1 answer:
Llana [10]3 years ago
6 0

Answer:

Step-by-step explanation:

Hi,

I am quite good at maths and will be happy to help you, not just in Algebra, but any other topics in maths

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Tom determines that the system of equations below has two solutions, one of which is located at the vertex of the parabola.
xxTIMURxx [149]

Answer:

Option A: b must equal 7 and a second solution to the system must be located at the point (2, 5)

Step-by-step explanation:

<u><em>The complete question is</em></u>

Tom determines that the system of equations below has two solutions, one of which is located at the vertex of the parabola.

Equation 1: (x – 3)2 = y – 4

Equation 2: y = -x + b

In order for Tom’s thinking to be correct, which qualifications must be met?

A: b must equal 7 and a second solution to the system must be located at the point (2, 5).

B: b must equal 1 and a second solution to the system must be located at the point (4, 5).

C: b must equal 7 and a second solution to the system must be located at the point (1, 8).

D: b must equal 1 and a second solution to the system must be located at the point (3, 4).

step 1

Find the vertex of the quadratic equation

The general equation of a vertical parabola in vertex form is

y=a(x-h)^2+k

where

(h,k) is the vertex

we have

(x-3)^{2}=y-4

so

y=(x-3)^{2}+4

The vertex is the point (3,4)

step 2

Find out the value of b in the linear equation

we know that

If the vertex is a solution of the system of equations, then the vertex must satisfy both equations

substitute the value of x and the value of y of the vertex in the linear equation

y=-x+b

For x=3, y=4

4=-3+b\\b=7

so

y=-x+7

step 3

Find out the second solution of the system of equations

we have

y=(x-3)^{2}+4 -----> equation A

y=-x+7 ----> equation B

solve the system of equations by graphing

Remember that the solutions are the intersection points both graphs

The second solution of the system of equations is (2,5)

see the attached figure

therefore

b must equal 7 and a second solution to the system must be located at the point (2, 5)

5 0
3 years ago
Read 2 more answers
How do I graph an inequality in one variable?
Masja [62]
It depends on the variable.

If it's something like x < 2, your graph would be a vertical line at x = 2, and everything to left of that line shaded in (because of the less than).

Similarly for y, except it would be a horizontal line with either everything above or below shaded.

You can have other equations like 0<x<4 where everything between x = 0 and x = 4 would be shaded
7 0
3 years ago
Please answer QUICKLY!!!
sergiy2304 [10]

Answer:

the range is {7,5,1}

Step-by-step explanation:

To find the range, just plug in the domain into the function.

f(-1) = -2(-1) + 5 = 7

f (0) = -2(0) + 5 = 5

f(2) = -2(2) + 5 = 1

8 0
2 years ago
Please help asap 25 pts
otez555 [7]

4(k+5)=2(9k-4)\qquad|\text{use distributive property}\\\\(4)(k)+(4)(5)=(2)(9k)+(2)(-4)\\\\4k+20=18k-8\qquad|\text{subtract 20 from both sides}\\\\4k=18k-28\qquad|\text{subtract 18k from both sides}\\\\-14k=-28\qquad|\text{divide both sides by -14}\\\\\boxed{k=2}\to\boxed{d.}

6 0
3 years ago
1. If a - b = 4 and a + b = 12, what is the<br> value of a?
Marta_Voda [28]
A=8

Explanation: a+b=12 a-b=4
^^^^^^^ ^^^^^^
8+4=12 8-4=4
A=8
8 0
3 years ago
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