Answer:
0.23328,2.4
Step-by-step explanation:
Given that an airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservations for a trip, and a passenger must have a reservation.
Assuming independence we can say persons who do not show up is binomial with p = 0.4 and n = 6
a) If six reservations are made, what is the probability that at least one individual with a reservation cannot be accommodated on the trip
= 
b) Expected no of available places = E(x)=
Answer:
-1
Step-by-step explanation:
We are given the expression:
-5x + 6y - 7y + 4x
With condition x = -3, y = 4
Therefore, substitute x = -3 and y = 4.
-5(-3) + 6(4) - 7(4) + 4(-3)
Recall every important fundamental math such as multiplying with negative.
15 + 24 - 28 - 12
Evaluate:
39 - 40
-1
Alternative solution is to combine like terms first before substitution.
-x - y
Thus:
-(-3) - 4
3 - 4
-1
Answer:
y = 1/5x + 2
Step-by-step explanation:
y = 1/5x + b
4 = 1/5(10) + b
4 = 2 + b
2 = b
I guess you mean:
X^2 - X - 6 and X^2 - 5X + 6
X^2 - X - 6 = (X + 2)(X − 3)
X^2 - 5X + 6 = (X − 2)(X − 3)
Based on that, their common factor is:
(X - 3)
Answer:
The bus would be 36 times late in 400 times of when Fred takes the bus
Step-by-step explanation:
Given that the probability of being the bus late is 0.09.
In order to find the number of times the bus will be late will be calculated by multiplying the total number of observations by probability.
It is also given that the total number of days he waits for bus is 400 times.
So,
The bus will be:
Hence,
The bus would be 36 times late in 400 times of when Fred takes the bus
