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3 years ago

48 seconds 5 minutes3 3 kato900

Mathematics

2 answers:

svet-max [94.6K]3 years ago

7 0

I’m sorry I don’t understand do you mean add them?

Aleks [24]3 years ago

5 0

Answer:

huh

Step-by-step explanation:

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PLEASE HELP IMMEDIATELY

MissTica

Answer:

Option B is the correct option.

Step-by-step explanation:

$- \frac{1}{2} + x = - \frac{21}{4}$

Move constant to R.H.S and change its sign:

$x = - \frac{21}{4} + \frac{1}{2}$

Take the L.C.M

$x = \frac{ - 21 + 1 \times 2}{4}$

$x = \frac{ - 21 + 2}{4}$

Calculate

$x = - \frac{19}{4}$

Hope this helps...

Good luck on your assignment..

7 0

4 years ago

Read 2 more answers

Please help me with question when your answering it make sure you explain it so I get it

IrinaK [193]

So plug in the number of passengers into each equation and see which answer matches Layton's. then from all the answers you find from plugging in the number of passengers, choose the cheapest one for B

4 0

4 years ago

A relation contains the points (2,3), (3,0), (4,1), (5,2), (5,0). Which statement accurately describes this relation

navik [9.2K]

Answer:

x,y

Step-by-step explanation:

6 0

3 years ago

JUST THE FIRST ONE EASY PLS ASAP

Sladkaya [172]

Answer:

<h2>For the first triangle, <u>x equals 22cm.</u></h2>

Here's how:-

x is the altitude or height of the triangle. To find it, we can use the Pythagoras theorem:-

$altitude^{2} + base^{2} = hypotenuse^{2}$

The base is 120cm and the hypotenuse is 122cm

Putting this in the equation, we get:-

$altitude^{2} + 120^{2} = 122^{2}$

$altitude^{2} = 122^{2}- 120^{2}$

$altitude^{2} = 14884 - 14400$

$altitude^{2}$ = 484

altitude = $\sqrt{484}$

<h3>altitude = 22cm</h3><h2><u>So, x = 22cm</u></h2>

7 0

3 years ago

A piece if wire 40cm is bent to form a right angled triangle whose hypotenuse is 17cm long find the other two sides of triangle

hjlf

Answer: 150mm

Step-by-step explanation:

Take the two adjecent sides of the triangle to be x and y and X is the angle opposite the side, x.

From the trigonometric identities for a right-angled triangle, it is known that

x=170sin X and;

y=170cos X

Thus the perimeter of the triangle is given by

170sin X + 170cos X + 170 = 400

170(sin X + cos X) = 400 - 170

170(sin X + cos X) = 230

sin X + cos X = 230/170 = 1.3529

Squaring both sides hence,

sin^2(X) + 2sin X.cos X + cos^2(X) = 1.8304

Recall that sin^2(X) + cos^2(X) = 1 and 2sin X.cos X = sin 2X.

Thus, the former expression gives;

1 + sin 2X = 1.8304

sin 2X = 0.8304

2X = arcsin (0.8304)

2X = 56.14° or (180 - 56.14)° = 56.14° or 123.86° for X existing within a triangle.

X = 56.14/2 or 123.86/2

X = 28.07° or 61.93°

Thus the two adjacent sides are ;

x = 170 sin (28.07) = 80mm

y = 170 cos (28.07) = 150mm

Using the value of 61.93° as X would give the same values but interchanged for x and y.

I hope you find this useful.

5 0

3 years ago

48 seconds 5 minutes3 3 kato900​

48 seconds 5 minutes3 3 kato900