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Gennadij [26K]
3 years ago
13

Solve each inequality. Justify each step (y-) - 4 + 2y > 11

Mathematics
1 answer:
Anna11 [10]3 years ago
4 0
It would stop at 3y+4>11 because the 3y and 4 are unlike terms and can only be divided or multiplied.
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Find the x - and y -intercepts of the following equation. <br>2 x + 3 y = − 24
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(2,3)

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Each month for 7 months, Samuel mows 3 lawns . How many more lawns does he need to mow before he has mowed 29 lawns
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Which of the following sets of numbers is a Pythagorean triple?
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Samuel charged me d dollars to fix my broken heater. He
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<u>$15 per hour</u>

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A machine makes two components; call them types A and B. It takes 250 seconds to switch production between the component types.
Alexus [3.1K]

Answer:

The average inventory depends on the manufacturing batch size.

Its formula is:

Inventory=\frac{n}{3n+250}

Step-by-step explanation:

The question is incomplete.

Question complete:

<em>"A machine makes two components, call them type A and B. It takes 250 seconds to switch production between the component types. During that time no production occurs. When in production, each unit of A or B requires 0.5 seconds to be completed. The two components, A and B are combined in an assembly process to make a final product, call it C. The assembly step can combine the two components into 1 unit every 2 seconds. What is the average inventory of B components?"</em>

We have two steps in this process: the manufacturing of A and B and the assembly process.

We are not told about the batch size, so we will treat that as a variable called n. This represents the amount of units (of A or B) that are manufactured per cycle.

Time (seconds) to manufacture n units of A and n units of B:

T_m=n*0.5+n*0.5+250=n+250

Time (seconds)to assemble n units of C

T_a=n*2=2n

Then the total time of the cycle is:

T_m+T_a=n+250+2n=3n+250

The average inventory of B is n units per cycle, which lasts (3n+250) seconds.

Inventory=\frac{n}{3n+250}

For a batch size of 100 units, the average inventory is:

I_{100}=\frac{100}{3*100+250}=\frac{100}{550}=  0.182\, units/second

For a batch size of 1,000 units, the average inventory is:

I_{1000}=\frac{1000}{3*1000+250}=\frac{1000}{3250}=  0.308\, units/second

5 0
3 years ago
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