5x = 35<br> full answer pls show your work

A ball is dropped from a height of 6 feet and begins bouncing. The height of each bounce is three-fourths the height of the prev

sesenic [268]

Theoretically, the answer is infinity. however, in a non perfect universe such as our own, practically the answer would be around 17ft.

8 0

4 years ago

Read 2 more answers

A container in form of a frustum of a cone is 16 cm in diameter at the open end and 24 cm diameter at the bottom. If the vertica

Nat2105 [25]

Answer:

The capacity of the container is 2546.78 cm³.

Step-by-step explanation:

The volume of the frustum of a cone is:

$\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]$

The information provided is:

r = 16/2 = 8 cm

R = 24/2 = 12 cm

h = 8 cm

Compute the capacity of the container as follows:

$\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]$

$=\frac{\pi\cdot8}{3}\cdot[(12)^{2}+(12\cdot 8)+(8)^{2}]\\\\=\frac{8\pi}{3}\times [144+96+64]\\\\=\frac{8\pi}{3}\times304\\\\=2546.784445\\\\\approx 2546.78$

Thus, the capacity of the container is 2546.78 cm³.

5 0

3 years ago

Are the mods awake or they sleep?

salantis [7]

Answer:

What is a mod?

Step-by-step explanation:

4 0

3 years ago

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you have $20:00 to spend on an Easter gift. you buy 1 dozen tulips for $15.35. with the money you have left, how many chocolate

kvasek [131]

All you’re doing is subtracting $15.35 from $20.00. After you get the answer, add $1.25 as many times as possible before it exceeds the number you got from the first subtraction.

$20.00 - 15.35 = $4.65
$1.25 x 3 = $3.75
(Anything over $3.75 would require additional money, so you couldn’t buy any more chocolate bunnies than 3.)

You could buy 3 chocolate bunnies after purchasing 1 dozen tulips for $15.35 with the remaining $4.65 you have left.

I struggle with math myself, so I’d recommend working it out on your own instead of pasting online answers because it pays off in the end! <3

5 0

2 years ago

The germination rate is the rate at which plants begin to grow after the seed is planted.

chubhunter [2.5K]

Answer:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

$\hat p=\frac{7}{15}=0.467$ estimated proportion of seeds germinated

$p_o=0.9$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:

Null hypothesis: $p\geq 0.9$

Alternative hypothesis: $p < 0.9$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

4 0

3 years ago

5x = 35 full answer pls show your work