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BabaBlast [244]
2 years ago
11

11

Advanced Placement (AP)
1 answer:
vovikov84 [41]2 years ago
5 0

Answer:

A,D,E

Explanation: just do it i had the same question

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if I want to become a doctor in the future. which program for high school is best, Advanced placement (ap) or International Bacc
uysha [10]

Answer:

I would personally recommend taking AP courses for any medical degree. Many colleges or universities consider AP and IB classes to be equal, and unless you are planning to go to college/university out of the US, Advanced Placement classes will be more accepted. Another reason why I would advise against IB classes is that it is not worth it to only take specific classes and is more beneficial to take the full diploma course. Some places will allow you to take individual classes instead of the full program like you would in AP, but it is not a guarantee. AP classes allow you to specialize more and avoid any classes you feel particularly weak in.

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Aside from an associates degree what else can you earn at a two year college
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You can earn multiple certificates and trades such as an automotive or mechanics trade would be an example
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Explain why a substance with a network structure has a high melting point.
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Silicon dioxide is dissolvable in water and has a high melting point because the atoms in the dioxide has a strong bond between them, which requires a lot of energy to break them.
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An example of good peer pressure would include
kari74 [83]

Answer:

Getting an after-school job and convincing friends to get a job too.

Explanation:

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2 years ago
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A ball is thrown into the air at a velocity of 44 feet per second. Its height in feet, h after t seconds is represented by the e
Lady_Fox [76]

Answer:

0.447 sec

Explanation:

velocity = distance/ time

distance 'h' is a function of time 't' given by

h = 12t^{2} + 44t + 16

⇒ differentiating equation

⇒ velocity = \frac{dh}{dt} = 24t + 44

⇒ acceleration = \frac{d^{2}h }{dt^{2} } = 24 \frac{ft}{sec^{2} }

deceleration due to gravity = -9.8 m/sec^{2} =  - 9.8 x 3.281 = - 32.154 ft/ sec^{2}

Net deceleration = 24 - 32.154 = - 8.15 ft/ sec^{2}

at maximum height v = 0

v^{2} = u^{2} + 2ah

⇒  0 = 44^{2} + 2 (-8.15)h

⇒ h = 118.72 ft⇒

118.72 = 12t^{2} + 44t + 16

⇒ 12t^{2} +44t - 102.72 = 0

⇒  t = -44 ± \sqrt{44^{2} - 4(12)(102.72) }     / (2 x 12)

t = 0.447 sec

6 0
3 years ago
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