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DerKrebs [107]
3 years ago
7

You and a friend go to the local taco joint for lunch. You order three tacos and three burritos and your bill totals $11.25. You

r friend's bill is $10.00 for 2 burritos and 4 tacos. Which system of equations can be used to determine the cost of b, a single burrito, and t, a single taco?
A.
3t + 3b = 10
2t + 4b = 11.25

B. 3t+ 3b = 11.25
2t + 4b = 10

C. 3t+ 3b = 10
4t + 2b = 11.25

D. 3t + 3b = 11.25
4t + 2b = 10​
Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:

d

Step-by-step explanation:

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Find the volume and surface area of this prism.
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Answer:

V = 408 cm cubed

SA = 558 cm squared

Step-by-step explanation:

To find the volume of a prism, multiply the area of the base by the height. This is 1/2 times width times height times length.

V =1/2 l*w*h =1/2* 6*8*17 = 408

To find the surface area of a prism, find the area of the triangular base and the area of each rectangular side.

Area of the base is A = 1/2 * b*h = 1/2 * 6 * 8 = 24. Since there are 2 bases, the area is 48.

Area of the rectangular side is A = b*h = 17*10 = 170. Since there are three, the area is 3*170 = 510.

The surface area of the prism is 48 + 510 = 558.

8 0
3 years ago
Suppose that you randomly draw one card from a standard deck of 52 cards. After writing down which card was drawn, you replace t
34kurt

Answer:

The probability is 0.0775

The expected value is 4.75 clubs

The standard deviation is 1.8875 clubs

Step-by-step explanation:

The variable X follows a binomial distribution, because we have n identical and independent events (19 cards) with a probability p of success and 1-p of fail (there is a probability of 1/4 to be club and 3/4 to be diamond, heart or spade). Then, the probability that x of the n cards are club is:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\P(x)=\frac{19!}{x!(19-x)!}*0.25^{x}*(0.75)^{19-x}

So, the probability P of drawing at least 8 clubs is:

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Replacing, the values of x, from 8 to 19, on the equation above, we get:

P = 0.0775

Additionally, the expected value E(x) and standard deviationS(x) for this distribution is given by:

E(x)=np = 19(0.25) = 4.75

S(x)=\sqrt{np(1-p)} =\sqrt{19(0.25)(0.75)} =1.8875

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3 years ago
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i did it on usatestprep

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C+s=48
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