Answer:
9 weeks
Step-by-step explanation:
Answer:
3 games
Step-by-step explanation:
The computation of the maximum number of games that he could buy is shown below:
= Amount available - already spent
= $75 - $28
= $47
If each game cost $15
So, the maximum no of games is
= $47 ÷ $15
= 3.133
= 3 games
9514 1404 393
Answer:
- (3y)(2x^2 -1x -8xy +4y)
- (3y)(x -4y)(2x -1)
Step-by-step explanation:
<u>Part A</u>: All of the coefficients have a common factor of 3. All of the variable products have a common factor of y, so the greatest common factor of all terms is 3y. The expression can be written as ...
(3y)(2x^2 -1x -8xy +4y)
__
<u>Part B</u>: The remaining factor can be factored pairwise:
3y(x(2x -1) -4y(2x -1)) = 3y(x -4y)(2x -1)
Answer:
y = 11
Step-by-step explanation:
8 × 2 + 5²- y = 2(y + 1) + 6
8 × 2 + 5²- y = 2y + 2 + 6
8 × 2 + 25 - y = 2y + 2 + 6
16 + 25 - y = 2y + 2 + 6
41 - y = 2y + 8
41 (- y + y) = (2y + y) + 8
41 = 3y + 8
41 - 8 = 3y (+ 8 - 8)
33 = 3y
33/3 = 3y/3
y = 11
