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strojnjashka [21]
2 years ago
14

At a historical landmark, candles are used to simulate an authentic atmosphere. A volunteer is currently putting new candles in

the candle holders. On the east side, he replaced candles in 24 small candle holders and 3 large candle holders, using a total of 87 candles. On the west side, he replaced the candles in 14 small candle holders and 7 large candle holders, for a total of 77 candles. How many candles does each candle holder hold?
Each small candleholder holds ____ candles, and each large one holds ____ candles
Mathematics
1 answer:
myrzilka [38]2 years ago
5 0

Answer:

Each small candleholder holds 3 candles, and each large one holds 5 candles.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of candles that a small candleholder holds.

y is the number of candles that a large candleholder holds.

24 small candle holders and 3 large candle holders, using a total of 87 candles.

This means that

24x + 3y = 87

Simplifying by 3

8x + y = 29

y = 29 - 8x

14 small candle holders and 7 large candle holders, for a total of 77 candles.

This means that 14x + 7y = 77

Simplifying by 7

2x + y = 11

y = 11 - 2x

Since y = 29 - 8x

11 - 2x = 29 - 8x

6x = 18

x = \frac{18}{6}

x = 3

y = 29 - 8x = 29 - 8*3 = 29 - 24 = 5

Each small candleholder holds 3 candles, and each large one holds 5 candles.

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lutik1710 [3]
This is the answer:)

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3 years ago
X²+Y²=250 and XY=117<br> What are the values of X and Y?
yan [13]

Answer:

<h3>            x = -9,  y = -13 </h3><h3>    or    x = 13,   y = 9</h3><h3>    or    x = -13,  y = -9</h3><h3>    or     x = 9,   y = 13</h3>

Step-by-step explanation:

x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad  x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}

y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Hope this helps

8 0
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Read 2 more answers
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