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Nikolay [14]
3 years ago
11

Please show all the steps and work. The answer is -3.9 m/s2

Physics
1 answer:
konstantin123 [22]3 years ago
8 0

Given that,

Initial velocity of the airplane = 66 m/s

Distance = 560 m

Final velocity of the airplane = 0 (stops)

To find,

Acceleration of the airplane.

Solution,

Let us consider that a is the acceleration of the airplane. We can find it using third equation of motion as follows :

v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{0^2-66^2}{2(560)}\\\\a=-3.9\ m/s^2

Therefore, the acceleration of the airplane is -3.9\ m/s^2

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Answer:

37.5m/s

Explanation:

momentum = mass x velocity

momentum / mass = velocity = speed

75kg*m/s / 2kg = 37.5m/s

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Which example involves the transformation of chemical energy directly into light energy?
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A certain refrigerator has a COP of 5.00. When the refrigerator is running, its power input is 500 W. A sample of water of mass
yulyashka [42]

Answer:

t=20s

Explanation:

To solve this problem we must apply the first law of thermodynamics, which indicates that the energy that enters a system is the same that must come out, resulting in the following equation

For this problem we will assume that the water is in a liquid state, since it is a domestic refrigerator

q=m.cp.(T2-T1)

q=heat

m=mass of water =600g=0.6Kg

cp=

specific heat of water=4186J/kgK

T2=temperature in state  2=20°C

T1=temperature in state 1=0°C

solving:

q=(0.6)(4186)(20-0)=50232J

A refrigerator is a device that allows heat to be removed to an enclosure (Qin), by means of the input of an electrical energy (W) and the heat output (Qout), the coefficient of performance COP, allows to know the ratio between the heat removed ( Qin) and the added electrical power (W), the equation for the COP is

COP=\frac{Qin}{Win}

To solve this exercise we must know the value of the heat removed to the water (Qin)

solving for Qin

Qin=(COP)(Win)

Qin=(5)(500W)=2500W

finally we remember that the definition of power is the ratio of work over time

w=work

p=power=500w

P=\frac{W}{t} \\t=\frac{W}{P} \\t=\frac{50232}{2500} \\t=20.09s

3 0
3 years ago
Why is a normal eye not able to see clearly the object placed closer than 25 CM?​
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Answer: The nearest position of an object from a normal human eye so that its image is formed on retina is 25 CM. If the object is placed at a distance less than 25 CM, then the blurred image of the object is formed on retina as the focal length of a lens cannot be decreased below a certain limit. Hence we cannot see it clearly.

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3 0
3 years ago
A diver leaves the end of a 4.0 m high diving board and strikes the water 1.3s later, 3.0m beyond the end of the board. Consider
shutvik [7]

Answer:

4.0 m/s

Explanation:

The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.

Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is

d=v_x t

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v_x = \frac{d}{t}=\frac{3.0 m}{1.3 s}=2.3 m/s

Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by

y(t) = h + v_y t - \frac{1}{2}gt^2

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h = 4.0 m is the initial height

vy is the initial vertical velocity

We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy

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So now we can find the magnitude of the initial velocity:

v=\sqrt{v_x^2+v_y^2}=\sqrt{(2.3 m/s)^2+(3.3 m/s)^2}=4.0 m/s

4 0
4 years ago
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