Answer:
Average force = 67 mn
Explanation:
Given:
Initial velocity u = 0 m/s
Final velocity v = 67 m/s
Time t = 1 ms = 0.001 sec.
Computation:
Using Momentum theory
Change in momentum = F × Δt
(v-u)/t = F × Δt
F × 0.001 = (67 - 0)/0.001
F= 67,000,000
Average force = 67 mn
About 21c because it also depends on the weather outside
Answer:
The maximum power density in the reactor is 37.562 KW/L.
Explanation:
Given that,
Height = 10 ft = 3.048 m
Diameter = 10 ft = 3.048 m
Flux = 1.5
Power = 835 MW
We need to calculate the volume of cylinder
Using formula of volume
Put the value into the formula
We need to calculate the maximum power density in the reactor
Using formula of power density
Where, P = power density
E = energy
V = volume
Put the value into the formula
Hence, The maximum power density in the reactor is 37.562 KW/L.
Answer:
500cal
Explanation:
Given parameters:
Mass of water = 50g
Initial temperature = 22°C
Final temperature = 32°C
Specific heat of water = 1cal/g
Unknown:
Amount of heat absorbed by the water in calories = ?
Solution:
To solve this problem, we use the expression below:
H = m c Ф
H is the amount of heat absorbed
m is the mass
c is the specific heat capacity
Ф is the temperature change
H = 50 x 1 x (32 - 22) = 500cal
Answer:
<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>
Explanation:
The Non conservative force is defined as a force which do not store energy or get he energy dissipate the energy from the system as the system progress with the motion.
Given are
<em> mass of the student 73 kg</em>
<em> height of water glide 11.8 m</em>
<em> work done as -5.5*10³ J</em>
Have to find speed at which the student goes down the glide.
According to<em> Law of Conservation of energy</em>,
K.E =P.E+Work Done
mv²/2=mgh +W
Rearranging the above eqn for v
v = √2(gh+W/m)
Substituting values,
V = 12.48 m/s.
<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>
