Answer:
In the numbers mumbo jumbo, 76 is the minimum and 89 is the maximum. So it can look like this. (Fig A)
If you understood Fig A, the rest is easy.
There are one 76s, one 77s, four 78s, no 79s, four 80s, five 81s, no 82s, five 84s, four 85s, one 86s, two 87s, one 88s, and two 89s in the mumbo jumbo.
So the completed dot plot would look like Fig B. (I drew this in the computer and the dots aren't presicely balanced, but you'll get the idea)
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:
P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:
P = 0.59