From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
Answer: Im not sure
Step-by-step explanation:
you didnt list/provide the graphs for me to answer. :I
Answer:
The given system has NO SOLUTION.
Step-by-step explanation:
Here, the given system of equation is:
6 x - 2 y = 5 .......... (1)
3 x - y = 10 .... (2)
Multiply equation 2 with (-2), we get:
3 x - y = 10 ( x -2)
⇒ - 6 x + 2 y = - 20
Now, ADD this to equation (1) , we get:
6 x - 2 y - 6 x + 2 y = 5 - 20
or, 0 = - 15
WHICH IS NOT POSSIBLE as 0 ≠ -15
Hence, the given system has NO SOLUTION.
Answer:
8 hours 48 mins
Step-by-step explanation:
h m
5:15
+3:33
--------------
8:48
or
5 hours + 3 hours =8 hours,
15 mins + 33 mins = 48 mins
Therefore, it's 8 hours 48 mins.
Answer:
h = A*2/a+b
Step-by-step explanation: