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3 years ago

PLEASEE SOMEONE HELP ANSWER CORRECTLY !!!!! WILL MARK BRIANLIEST !!!!

Mathematics

1 answer:

Vlad1618 [11]3 years ago

5 0

Answer:

NT and MT

Step-by-step explanation:

Sorry I'm late lol.

The two segments form a right angle where they intersect, which is a common indication of perpendicular lines.

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Given that the diameter of Circle A is 6 cm , and the radius of Circle B is 18 cm , what can be concluded about the two circles?

ELEN [110]

Answer:

The radius of circle B is 6 times greater than the radius of circle A

The area of circle B is 36 times greater than the area of circle A

Step-by-step explanation:

we have

<em>Circle A</em>

$D=6\ cm$

The radius of circle A is

$r=6/2=3\ cm$ -----> the radius is half the diameter

<em>Circle B</em>

$r=18\ cm$

Compare the radius of both circles

$3\ cm< 18\ cm$

$18=6(3)$

The radius of circle B is six times greater than the radius of circle A

Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared

All circles are similar

In this problem the scale factor is 6

$6^{2}=36$

therefore

The area of circle B is 36 times greater than the area of circle A

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3 years ago

Find the number of rooms per hour that Jake, Lionel, and Donald can paint working together if t is 6 hours.

lara31 [8.8K]

You dont have a complete question

7 0

3 years ago

The only solution of the equation x^2 + bx + 16 = 0 is x = 4. What is the value of b?

jeka94

Answer:

yes beacajdkdnjdhdhds

Step-by-step explanation:

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2 years ago

Choose the greatest of the four

iragen [17]

Answer:

D 1.33

Step-by-step explanation:

B and C are less than 1

A is one and .30

D is one and .33

33>30

4 0

3 years ago

Read 2 more answers

How do you do this trig problem.

loris [4]

Consider a right triangle in which one of the angles $\theta$ satisfies

$\sin\theta=\dfrac35\implies\theta=\sin^{-1}\dfrac35$

That is, the side opposite $\theta$ occurs in a ratio of 3 to 5 with the hypotenuse. The side adjacent to $\theta$ then occurs in a ratio of 4 to 5 with the hypotenuse. In other words,

$\cos\theta=\dfrac45$

because

$\sin^2\theta+\cos^2\theta=\dfrac9{25}+\dfrac{16}{25}=1$

Then in this triangle,

$\cot\theta=\cot\left(\sin^{-1}\dfrac35\right)=\dfrac{\cos\theta}{\sin\theta}=\dfrac{\frac45}{\frac35}=\dfrac43$

7 0

3 years ago