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Gennadij [26K]
3 years ago
15

A marshmallow has an initial volume of 0.027 L at standard pressure (1.0 atm). If the marshmallow is placed in a vacuum chamber

and the final volume is 0.205L, what is the pressure inside the chamber?
A marshmallow has an initial volume of 0.027 L at standard pressure (1.0 atm). If the marshmallow is placed in a vacuum chamber and the final volume is 0.205L, what is the pressure inside the chamber?
Chemistry
1 answer:
MatroZZZ [7]3 years ago
6 0

Answer:

The pressure inside the chamber is 0.132 atm

Explanation:

Step 1: Data given

The initial volume = 0.027 L

The initial pressure = 1.0 atm

The volume changes to 0.205 L

Step 2: Calculate the pressure

P1*V1 = P2*V2

⇒with P1 = the initial pressure = 1.0 atm

⇒with V1 = the initial volume = 0.027 L

⇒with P2 = the changed pressure = TO BE DETERMINED

⇒with V2 = the changed volume = 0.205 L

1.0 atm *0.027 L = P2*0.205 L

P2 = 0.027/0.205

P2 = 0.132 atm

The pressure inside the chamber is 0.132 atm

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The answer to your question is  CH₄

Explanation:

Process

1.- Write the possible chemical reaction

                   CxHy + O₂   ⇒    CO₂  +   H₂O

2.- Calculate the amount of carbon in the reaction

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                         44 g of CO₂ ------------------- 12 g of carbon

                         93.5 g of CO₂ ----------------  x

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3.- Calculate the mass of hydrogen in the sample

Molecular mass of water = 2 + 16 = 18 g

                         18 g of water -------------   2 g of hydrogen

                          76.5 g of water --------    x g of hydrogen

                           x = (76.5 x 2) / 18

                           x = 8.5 g of hydrogen

4.- Calculate the moles of carbon and hydrogen in the sample

                           12g of carbon ------------- 1 mol

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                             x = (25.5 x 1) / 12

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carbon = 2.12 / 2.12 = 1

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6.- Write the molecular formula

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