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2 years ago

Scientists estimate between 10,000,000 and 50,000,000 monarch

Mathematics

2 answers:

frozen [14]2 years ago

4 0

Answer:

Step-by-step explanation:The Monarch Butterfly Biosphere Reserve is a World Heritage Site containing most of the ... The monarch butterflies migration patterns are altered by climate change. During migration ... This area is predominantly covered in forests. ... These colonies are dense, with between six and sixty million butterflies per hectare.

Helen [10]2 years ago

4 0

Answer:

80,000,000

Step-by-step explanation:

The difference between 10,000,000 and 50,000,000 is 40,000,000 per hectare. The question states two hectares, so 40,000,000 x 2 is 80,000,000.

Hope that helps.

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Researchers conducted a study to determine whether magnets are effective in treating back pain. Pain was measured using the visu

Kay [80]

Answer:

10 step

Step-by-step explanation:

6 0

2 years ago

A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude

EleoNora [17]

Answer:

a) $P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)$

And we can use the probability mass function and we got:

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

And adding we got:

$P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061$

b) $P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182$

c) $P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]$

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

$P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054$

And replacing we got:

$P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886$

d) $E(X) = 20*0.2= 4$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=20, p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

We want this probability:

$P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)$

And we can use the probability mass function and we got:

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

And adding we got:

$P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061$

Part b

We want this probability:

$P(X=4)$

And using the probability mass function we got:

$P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182$

Part c

We want this probability:

$P(X>3)$

We can use the complement rule and we got:

$P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]$

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

$P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054$

And replacing we got:

$P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886$

Part d

The expected value is given by:

$E(X) = np$

And replacing we got:

$E(X) = 20*0.2= 4$

3 0

2 years ago

What is the common difference, d, in the arithmetic sequence defined by the formula below? an=2n+1

marishachu [46]

<h3><u>Answer:</u></h3>

d = 2

<h3><u>Solution:</u></h3>

We are given that the arithmetic progression is defined by :

➝ 2n + 1

<em>Therefore, </em>

<u>For </u><u>first </u><u>term</u>

➙ n = 1

➝ 2 × 1 + 1

➝ 2 + 1

➝ 3

<u>For </u><u>second </u><u>term</u>

➙ n = 2

➝ 2 × 2 + 1

➝ 4 + 1

➝ 5

<u>Common </u><u>difference</u>

➙ 2nd term - 1st term

➝ 5 - 3

➝ 2

<h3><u>More </u><u>information</u><u>:</u></h3>

The difference between the successive term and the preceding term is the difference of an arithmetic progression. It is always same for the same arithmetic progression.

5 0

2 years ago

Over the summer, for every 14 Okra seeds Dana planted, 9 plants grew. If he planted 182 seeds, how many grew into plants?

vova2212 [387]

Simple...

you have: For every 14 seeds that Okra seeds Dana planted 9 of them grew; if he planted 182 seeds..how many grew?

Set up an equation...

$\frac{9}{14} = \frac{x}{182}$

Cross multiply....

14*x=14x

9*182=1638

14x=1638

$\frac{14x}{14} = \frac{1638}{14} =117
$

x=117

This means that, for 182 seeds planted, 117 of them grew to be plants.

Thus, your answer.

3 0

3 years ago

Read 2 more answers

Lucia is wrapping packages that are in the shape of a triangular prism. The net of the prism is shown below: ( Help me answer th

solniwko [45]

Answer:

The total surface area of all 6 prisms is 6336 in^2.

Step-by-step explanation:

Let's find the surface area of ONE prism and then multiply that result by 6 to obtain the final answer.

One prism:

The area of the two 13 in by 26 in rectangular tabs is 2(13 in)(26 in), or 676 in^2 (subtotal);

The area of the two triangles of base 10 in and height 12 in is 2([1/2][10 in][12 in], or 120 in^2; and, finally,

The area of the 10 in by 26 in base is 260 in^2.

The total surface area of ONE prism is thus:

676 in^2 + 120 in^2 + 260 in^2, or 1056 in^2.

Now, because there are 6 of these prisms, multiply this last result by 6:

6(1056 in^2) = 6336 in^2.

The total surface area of all 6 prisms is 6336 in^2.

7 0

3 years ago