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IRINA_888 [86]
3 years ago
7

What is the value of the 1 in the following number. 2043.61

Mathematics
2 answers:
timama [110]3 years ago
7 0

Answer:

hundredths

Step-by-step explanation:

• right from the decimal point, the first value that comes starts from tens rather then ones

• we always add ' ths ' in every value from right to the decimal point

kompoz [17]3 years ago
4 0
The answer for this is hundredth because it is .01 (two values behind decimal means hundredths)
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2(5x-7)=2x+10 what Is the distributive property
Lilit [14]

Answer:

X = 3

Step-by-step explanation:

first you would do 2 * 5x - 2 * 7 = 2x+10

second you'll get 10x- 14 = 2x + 10

third subtract the 2x by the 10x

fourth you'll get 8x

fifth then add the 14 to the 10

sixth 8x = 24

divide that by 8x to both sides

so then you get x=3

8 0
3 years ago
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.
Ilya [14]

Answer:

B. cost(time)

Step-by-step explanation:

In the information given above, you can eliminate choices "A," and "D," since they're just using the cost of a repair and the time the mechanic works. This leaves us with either "B," or "C." The correct answer is "B," because the cost of the repair depends on whatever is inside the parenthesis (the time).

3 0
4 years ago
If f(x)= x2/x+3, find f(x+h)?
kompoz [17]

f(x+h) =  \frac{x^{2}+2xh+h^{2}  }{x+h+3}

Step-by-step explanation:

Given,

f(x) = \frac{x^{2} }{x+3}

To find the value of f(x+h) we need to replace x by x+h

Hence,

f(x+h) = \frac{(x+h)^{2} }{x+h+3}

= \frac{x^{2}+2xh+h^{2}  }{x+h+3}

[Here, we apply the formula of (a+b)^{2}= a^{2} +2ab+ b^{2}]

6 0
3 years ago
If anyone know this can you help !
GrogVix [38]

Answer:

It is 8 ft I think.

3 0
3 years ago
Read 2 more answers
Find the extreme values of the function and where they occur. f(x)=x-4sqrt(x)
Tema [17]
The extreme values of the function f(x) = x - 4sqrt(x) occur at the values of x for which f'(x) = 0

f'(x) = 1 - 2/sqrt(x) = 0
sqrt(x) - 2 = 0
sqrt(x) = 2
x = 4
To check for minimum or maximum,
f''(x) = 1/(sqrt(x))^3 = 1/(sqrt(4))^3 = 1/(2^3) = 1/8 => the point is a minimum.

Therefore, the minimum value = f(4) = 4 - 4sqrt(4) = 4 - 4(2) = 4 - 8 = -4 and occurs at x = 4.
3 0
3 years ago
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