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USPshnik [31]
3 years ago
6

Two cylinders contain pistons that are connected by fluid in a hydraulic system. A force of 1,300 N is exerted on one piston wit

h an area of 0.05 m2. What is the force exerted on the other piston that has an area of 0.08 m?​
Physics
1 answer:
Anastasy [175]3 years ago
4 0

Given :

Two cylinders contain pistons that are connected by fluid in a hydraulic system.

A force of 1,300 N is exerted on one piston with an area of 0.05 m².

To Find :

The force exerted on the other piston that has an area of 0.08 m.

Solution :

Since, force is exerted between two cylinder, it means pressure is constant.

So,

P_1 = P_2\\\\\dfrac{F_1}{A_1} = \dfrac{F_2}{A_2}\\\\\dfrac{1300\ N}{0.05 \ m^2} = \dfrac{F_2}{0.08\ m^2}\\\\F_2 = \dfrac{1300\times 0.08}{0.05}\ N\\\\F_2 = 2080\ N

Hence, this is the required solution.

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Answer

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