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Pavlova-9 [17]
3 years ago
15

Which method would likely use less energy? (1) Pushing the heavy box at a slow, constant pace or (2) Pushing the heavy box in fa

st bursts with breaks in between?
Physics
1 answer:
MrMuchimi3 years ago
6 0
1 would use less energy. Please vote my answer brainliest! Thanks.
You might be interested in
Can someone answer these questions
Aleks04 [339]

Answer:

1. Following the recoil principle, rockets use combustion (a controlled explosion) to work against earth's gravitational attraction.

2. A force is a push or a pull that acts upon an object as a results of its interaction with another object. ... These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction.

(via physicsclassroom.com)

3. The combustion throws out material with very high momentum and is, physically speaking, the action. In reaction to that that, the rocket moves away from it (upward when in starts and has the action underneath it)

4. To show the world that commercial manned space missions are safely possible. Some may also like the fact that the US can now do, or rather order, manned flights into space without the help of the russian space agency (Roskosmos).

5. Robert Behnken and Douglas Hurley

6. The international space station (ISS)

7. Yes, Stage 1 of the rocket landed on the drone ship. The crew opened the hatch to enter the space station after 21 hours and 39 minutes after the launch from Cape Canaveral.

8. To have private contractors such as SpaceX actively in the field, there are now more interest groups that participate in space travel. And they can interact with other companies as well.

Also, due to Musks dream and efforts of SpaceX, space travel seems to get a lot cheaper.

That might indeed open the way back to the moon and further to the Mars for human space flight.

Governments such as the US planned on such things for decades, but changed plans ever since, and routinely changed leadership and the opinion on what's important.

Now Spaceflights can become less politically motivated and more commercially. That seems to be a more stable way over long periods of time.

(wrote most of it for you myself, even tough I'm not a native English speaker. would really appreciate the brainliest if you appreciate the work)

5 0
3 years ago
Read 2 more answers
How much force is required to accelerate a 5 kg mass at 20 m/s^2
Studentka2010 [4]

Hello!

\large\boxed{F = 100N}

Use the equation F = m · a (Newton's Second Law) to solve. Substitute in the given values:

F = 5 · 20

F = 100N

6 0
3 years ago
Consider three scenarios in which a particular box moves downward under the pull of gravity :
luda_lava [24]

Answer:

1. True  WA > WB > WC

Explanation:

In this exercise they give work for several different configurations and ask that we show the relationship between them, the best way to do this is to calculate each work separately.

A) Work is the product of force by distance and the cosine of the angle between them

    WA = W h cos 0

   WA = mg h

B) On a ramp without rubbing

     Sin30 = h / L

     L = h / sin 30

     WB = F d cos θ  

     WB = F L cos 30

     WB = mf (h / sin30) cos 30

     WB = mg h ctan 30

C) Ramp with rubbing

    W sin 30 - fr = ma

   N- Wcos30 = 0

   W sin 30 - μ W cos 30 = ma

    F = W (sin30 - μ cos30)

   WC = mg (sin30 - μ cos30) h / sin30

   Wc = mg (1 - μ ctan30) h

When we review the affirmation it is the work where there is rubbing is the smallest and the work where it comes in free fall at the maximum

Let's review the claims

1. True The work of gravity is the greatest and the work where there is friction is the least

2 False. The job where there is friction is the least

3 False work with rubbing is the least

4 False work with rubbing is the least

5 0
3 years ago
Billiard ball A (0.35 kg) is struck such that it moves at 10 m/s toward a second identical ball (Ball B) initially at rest. Afte
timurjin [86]

Answer:

Explanation:

We shall apply law of conservation of momentum during the collision of ball A and B .

Total momentum before collision of A and B = .35 x 10 = 3.5 kg m/s

Let the velocity of B after collision be v .

Total momentum after collision  = .35 x 2 + .35v

According to law of conservation of momentum

.35 x 2 + .35v  = 3.5

.35 v = 2.8

v = 8 m /s .

The direction of B will be same as direction of A .

3 0
3 years ago
A 60 N force is applied over a distance of 15 m. How much work was done?
GuDViN [60]

Answer:

900J

Explanation:

w =f×s

60×15

=900J

thus the k.e of the body is 900j

3 0
2 years ago
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