The difference between an experimental value and an accepted value is
1 answer:
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Answer:
Dy = 111.66 [m]
t = 3.5 [s]
Explanation:
To solve this problem we must use the equations of kinematics.
where:
Vf = final velocity [m/s]
Vo = initial velocity = 27 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time = 3.5 [s]
Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction
Vf = 27 - (9,81*3,5)
Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)
To find how high the snowball was we must use the following equation:
Dy = (27*3.5) + (0.5*9.81*3.5)
Dy = 94.5 + (17.16)
Dy = 111.66 [m]
Answer:
W = 1884J
Explanation:
This question is incomplete. The original question was:
<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>
<em> How much work W does the motor do on the platform during this process? Enter your answer in joules to four significant figures.</em>
The amount of work done by the motor is given by:
Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.
By using kinematics:
But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:
=>
Now we can calculate the final velocity:
Finally, we calculate the total work:
Since the question asked to "<em>Enter your answer in joules to four significant figures.</em>":
W = 1884J