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topjm [15]
3 years ago
8

11. In conflict resolution, promotes____ a win-lose outcome.

Physics
1 answer:
evablogger [386]3 years ago
3 0

negotiation.

<em>S</em><em>A</em><em>N</em><em>A</em><em> </em><em>M</em><em>A</em><em>K</em><em>A</em><em>T</em><em>U</em><em>L</em><em>O</em><em>N</em><em>G</em><em>.</em>

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The total number of protons plus neutrons in an atom of ⁴⁵₂₀Ca is
umka2103 [35]

Answer:

D)

Explanation:

The number of protons plus neutrons in an atom of 45 and 20ca is 65.

3 0
4 years ago
We can determine the velocity of a wave when given the frequency and the
Kobotan [32]

Hello.

The answer is: D. wavelength

This is correct because   frequency x wavelength = speed

Have a nice day

3 0
3 years ago
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You are riding a bicycle. If you apply a forward force of 125 N, and you and your bicycle have a mass of 86 kg, what will be the
Karolina [17]

Answer: B 1.52 m/s hope this helps

Explanation: I just took the test

3 0
3 years ago
Capillary action in trees can transport water from the roots to the tree's branches. The capillaries (Xyelem) in a certain tree
lesantik [10]

Answer:

h=14.2857\,m

Explanation:

Given:

radius of capillary, r=10^{-6}\,m

angle of contact, \theta=0^{\circ}

density of water, \rho=1000\,kg.m^{-3}

surface tension of water, T=0.07 \,N.m^{-1}

height, h = ?

We have the equation for the height of meniscus as:

h=\frac{2T.cos\, \theta}{\rho.g.r}

h=\frac{2\times 0.07\times cos\,0^{\circ}}{1000\times 9.8\times 10^{-6}}

h=14.2857\,m

No, the capillary action alone cannot be the mechanism of water transportation to the top of the trees. Transpiration also creates a suction pressure in the xylem complementary to the ascent of sap and cohesion of water being the other causes of movement of water up in the plants.

6 0
3 years ago
From a branch 35 m high, a 0.75 kg bird dives into a small fish tank containing
Bad White [126]

Answer:

ΔT = 1.22*10^-3 °C

Explanation:

First, you calculate the potential energy of the bird when it is at 35 m high. The potential energy is also the mechanical energy of the bird in this case.

U=mgh

m: mass of the bird = 0.75kg

g: gravitational constant = 9.8m/s^2

h: height = 35m

U=(0.75kg)(9.8m/s^2)(35m)=257.25\ J

All this energy is given to the water. You use the following formula in order to calculate the change in temperature:

Q=mc\Delta T

m: mass of the water = 50kg

c: specific heat of water = 4186 J/kg°C

Q is equal to U (potential energy of the bird) because the bird gives all its energy to water. By doing ΔT the subject of the formula you obtain:

\Delta T=\frac{Q}{mc}=\frac{257.25J}{(50kg)(4186J/kg°C)}=1.22*10^{-3}\ \°C

hence, the maximum rise in temperature is 0.00122 °C

7 0
3 years ago
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