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laila [671]
3 years ago
15

We can determine the velocity of a wave when given the frequency and the

Physics
2 answers:
antoniya [11.8K]3 years ago
7 0

Answer:

d. wavelength

Explanation:

The velocity of a wave is product of its wavelength and frequency. Frequency refers to the vibrations per second and wavelength is the distance between two successive troughs(highest point of wave) or crests(lowest point of wave). Since frequency is already given we need wavelength of the wave to find out its velocity. The velocity is independent of its amplitude (intensity).

Kobotan [32]3 years ago
3 0

Hello.

The answer is: D. wavelength

This is correct because   frequency x wavelength = speed

Have a nice day

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An 97 kg climber climbs to the top of Mount Everest, which has a peak height of 8850 m above sea level. What is the climber’s po
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Eg=mgh
Eg=(97)(9.8)(8850)
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3 years ago
How does light behave when a laser is pointed at a prism?
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So when you shine a laser through a prism, there's nothing to be separated, and the light stays together.

Explanation:

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2 years ago
If the bonds in the reactants of Figure 7-3 contained 432 kJ of chemical energy and the bonds in the
Yuri [45]

Answer:

  • <u>The energy change would be 46kJ</u>
  • <u>The energy would be absorbed</u>

Explanation:

The <em>energy change </em>during a chemical reation, i.e. the reaction energy, is equal to the chemical energy stored in the<em> bonds of the products </em>less the chemical energy stored in the <em>bonds of the reactants</em>.

Hence:

  • <em>Energy change</em> = 478 kJ - 432kJ = 46kJ

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4 0
3 years ago
A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
Marrrta [24]

Answer:

h = 2.64 meters      

Explanation:

It is given that,

Mass of one ball, m_1=3\ kg

Speed of the first ball, v_1=20\ m/s (upward)

Mass of the other ball, m_2=2\ kg

Speed of the other ball, v_2=-12\ m/s (downward)

We know that in an inelastic collision, after the collision, both objects move with one common speed. Let it is given by V. Using the conservation of momentum to find it as :

V=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}

V=\dfrac{3\times 20+2\times (-12)}{3+2}

V = 7.2 m/s

Let h is the height reached by the combined balls of putty rise above the collision point. Using the conservation of energy as :

mgh=\dfrac{1}{2}mV^2

h=\dfrac{V^2}{2g}

h=\dfrac{7.2^2}{2\times 9.8}

h = 2.64 meters

So, the height reached by the combined mass is 2.64 meters. Hence, this is the required solution.

5 0
3 years ago
I run around a circular track, with radius 25m, for 4 and times before stopping. It takes me 16
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Answer:

13m/s. is the answer probably but do u have ms gallup too?

4 0
2 years ago
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