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3 years ago

We can determine the velocity of a wave when given the frequency and the

Physics

2 answers:

antoniya [11.8K]3 years ago

7 0

Answer:

d. wavelength

Explanation:

The velocity of a wave is product of its wavelength and frequency. Frequency refers to the vibrations per second and wavelength is the distance between two successive troughs(highest point of wave) or crests(lowest point of wave). Since frequency is already given we need wavelength of the wave to find out its velocity. The velocity is independent of its amplitude (intensity).

Kobotan [32]3 years ago

3 0

Hello.

The answer is: D. wavelength

This is correct because frequency x wavelength = speed

Have a nice day

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3 years ago

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3 years ago

A train traveling at 25 m/s is blowing its whistle at 440 Hz as it crosses a level crossing. You are waiting at the crossing and

ohaa [14]

Answer:

b) 472HZ, 408HZ

Explanation:

To find the frequencies perceived when the bus approaches and the train departs, you use the Doppler's effect formula for both cases:

$f_o=f\frac{v_s+v_o}{v_s-v}\\\\f_o=f'\frac{v_s-v_o}{v_s+v}\\\\$

fo: frequency of the source = 440Hz

vs: speed of sound = 343m/s

vo: speed of the observer = 0m/s (at rest)

v: sped of the train

f: frequency perceived when the train leaves us.

f': frequency when the train is getTing closer.

Thus, by doing f and f' the subjects of the formulas and replacing the values of v, vo, vs and fo you obtain:

$f=f_o\frac{v_s-v}{v_s+v_o}=(440Hz)\frac{340m/s-25m/s}{340m/s}=408Hz\\\\f'=f_o\frac{v_s+v}{v_s-v_o}=(440Hz)\frac{340m/s+25m/s}{340m/s}=472Hz$

hence, the frequencies for before and after tha train has past are

b) 472HZ, 408HZ

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3 years ago