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3 years ago

Please help out. I do not understand at all.

Mathematics

2 answers:

Kay [80]3 years ago

7 0

It’s c x=5 that what it is lol

Fofino [41]3 years ago

4 0

Answer:

Step-by-step explanation:

I think it is a ratio problem since the sides and trapezoid are congruent

It appears to be simplier than I thought. Each NEW base decreases EVERY equal step up by the SAME amount

The difference between the the bottom base and middle base is 3.5

21 - 17.5 = 3.5

The difference between the middle base and the top base is the same 3.5 so

17.5 - 3.5 = 14 is the length of the top base 3x + 2

so 3x + 2 = 14

3x = 14 - 2

3x = 12

x = 4 FINAL ANSWER

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Y-1/6x+5=0

Triss [41]

Answer:

-1/6x + y = -5 or option D

Step-by-step explanation:

standard form is ax + by = c

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3 years ago

Select the correct answer.

diamong [38]

Answer:

1 solution

Step-by-step explanation:

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8 0

3 years ago

Simplify, state all restrictions.

Kipish [7]

The simplified expression is $\frac{1 - x - y}{x + y}$ and the restriction is $y \ne -x$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\frac{x - y}{4x^2 - 8xy + 3y^2} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{x^2 - y^2} -1$

Express x^2 - y^2 as (x + y)(x - y) and factorize other expressions

$\frac{x - y}{(2x - y)(2x - 3y)} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1$

Rewrite the expression as products

$\frac{x - y}{(2x - y)(2x - 3y)} \times \frac{2x - 3y}{2x + y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1$

Cancel out the common factors

$\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{4x^2 - y^2}{(x + y)} -1$

Express 4x^2 - y^2 as (2x - y)(2x + y)

$\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{(2x - y)(2x + y)}{(x + y)} -1$

Cancel out the common factors

$\frac{1}{x + y} -1$

Take the LCM

$\frac{1 - x - y}{x + y}$

Hence, the simplified expression is $\frac{1 - x - y}{x + y}$ and the restriction is $y \ne -x$