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meriva
3 years ago
5

Integrate 1/x(x-1) dx

Mathematics
1 answer:
amm18123 years ago
7 0

Decompose the integrand into partial fractions:

1 / (<em>x</em> (<em>x</em> - 1)) = 1/(<em>x</em> - 1) - 1/<em>x</em>

Then

∫ 1 / (<em>x</em> (<em>x</em> - 1)) d<em>x</em> = ln|<em>x</em> - 1| - ln|<em>x</em>| + C = ln|1 - 1/<em>x</em>| + C

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SOVA2 [1]

Answer:

Step-by-step explanation:

600,399

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Anastasy [175]

Answer:

(a) x = -2y

(c) 3x - 2y = 0

Step-by-step explanation:

You can tell if an equation is a direct variation equation if it can be written in the format y = kx.

Note that there is no addition and subtraction in this equation.

Let's put these equations in the form y = kx.

(a) x = -2y

  • y = x/-2 → y = -1/2x
  • This is equivalent to multiplying x by -1/2, so this is an example of direct variation.

(b) x + 2y = 12

  • 2y = 12 - x
  • y = 6 - 1/2x
  • This is not in the form y = kx since we are adding 6 to -1/2x. Therefore, this is <u>NOT</u> an example of direct variation.

(c) 3x - 2y = 0

  • -2y = -3x
  • y = 3/2x
  • This follows the format of y = kx, so it is an example of direct variation.

(d) 5x² + y = 0

  • y = -5x²
  • This is not in the form of y = kx, so it is <u>NOT</u> an example of direct variation.

(e) y = 0.3x + 1.6

  • 1.6 is being added to 0.3x, so it is <u>NOT</u> an example of direct variation.

(f) y - 2 = x

  • y = x + 2
  • 2 is being added to x, so it is <u>NOT</u> an example of direct variation.

The following equations are examples of direct variation:

  • x = -2y
  • 3x - 2y = 0
7 0
3 years ago
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Type the correct answer in each box. Spell all words correctly, and use numerals instead of words for numbers. If necessary, use
Firlakuza [10]
Given:
2 rectangular prism.
same height
square bases


                                    Box A     Box B
Square Base side          2 ft        0.75 ft
Height                            4 ft        4 ft

Solving for the space inside each rectangular prism, we need to find its volume.

Volume of a rectangular prism = length * width * height

Box A: 
Volume = 2 ft * 2 ft * 4 ft = 16 cubic feet

Box B:
Volume = 0.75 ft * 0.75 ft * 4 ft = 2.25 cubic feet

Box A - Box B = difference in space

16 cubic feet - 2.25 cubic feet = 13.75 cubic feet

Box A contains 13.75 cubic feet more space than Box B. 
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The shaded sector above covers 1/3 of the circle. If the radius of the circle above is 3 cm, what is the area of the sector in t
Mekhanik [1.2K]

Given:

The shaded sector above covers \dfrac{1}{3} of the circle.

Radius of the circle = 3 cm

To find:

The area of the sector in terms of π.

Solution:

The area of a circle is

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Substituting r=3, we get

A=\pi (3)^2

A=9\pi

It is given that the shaded sector above covers \dfrac{1}{3} of the circle.

The area of shaded sector =\dfrac{1}{3}A

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                                             =3\pi

Therefore, the area of shaded sector is 3π sq. cm.

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Answer:

the 11 inch big zip for 7.75

Step-by-step explanation:

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