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ladessa [460]
3 years ago
14

Write out the sample space for the given experiment. Use the letter R to indicate red, G to indicate green, and B to indicate bl

ue. A die shows 33 different colors on it. Give the sample space for the next 22 rolls.
Mathematics
1 answer:
Vilka [71]3 years ago
3 0

Answer:

Answer for the question:

Write out the sample space for the given experiment. Use the letter R to indicate red, G to indicate green, and B to indicate blue. A die shows 33 different colors on it. Give the sample space for the next 22 rolls.

is given in the attachment.

Step-by-step explanation:

Download pdf
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iris [78.8K]

This equation has no solution

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What is 56 times 67899
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Answer:

435689

Step-by-step explanation:

6 0
3 years ago
When measuring time, 8 concerts are approximately equal to 6 symphonies. How many symphonies are equal to 42 symphonies?
Vinil7 [7]
So normally it is
if 8x is to 6y, then how many x is to 42y?
it could be
if 8x:6y then how many x:42y or
if 8x:6y then how many y:42 x

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if it is
x:42y go to AAAAAAAA
if it is
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AAAAAAAA
 how many concerts are equal to 42 symponies
arrange in concerts to symponies format

8:6=x:42
fractionify
8/6=x/42
multiply boht sides by 42
336/6=x
56=x
56 concerts equals 42 symponies



BBBBBBBBBB

 how many  symponies are equal to 42 concerts
areange in symponies:concerts
6:8=x/42
fractionify
6/8=x/42
multiply boht sides by 42
252/8=x
31.5=x
31.5 symponies to 42 concerts




so it could be


56 concerts to 42 symponies
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6 0
3 years ago
Find the critical numbers and the intervals on which the function f(x)=9x5−3x3+6f(x)=9x5−3x3+6 is increasing or decreasing. Use
Ierofanga [76]

Answer:

x = (0, -√(3/5), √(3/5)) are the critical points.

Local maximum at √(3/5), and local minimum is at -√(3/5).

The function is increasing in the interval

(−∞, -√(3/5)) U (√(3/5), ∞)

And decreasing in the interval

(-√(3/5), 0) U (0, √(3/5))

Step-by-step explanation:

Given the function

f(x) = 9x^5 - 3x³ + 6

First of all, take the first derivative of this, to have

f'(x) = 45x^4 - 27x²

The critical point are the points where the first derivative vanishes, that is

f'(x) = 0

Now, solve the equation

45x^4 - 27x² = 0

9x²(5x² - 3) = 0

x = 0 twice

Or

5x² - 3 = 0

5x² = 3

x² = 3/5

x = ±√(3/5)

So, x = (0, -√(3/5), √(3/5)) are the critical points.

Local maximum is when f'(x) > 0, this is √(3/5) in this case,

and local minimum is when f'(x) < 0, this is -√(3/5) in this case.

Now, we need to test for the various intervals to determine where the function increases and decreases.

(−∞, -√(3/5)):

f'(-√(4/5)) = 45(-√(4/5))^4 - 27(-√(4/5))²

= 36/5 > 0. Increasing

(-√(3/5), 0):

f'(-√(2/5)) = 45(-√(2/5))^4 - 9(-√(2/5))²

= -18/5 < 0. Decreasing

(0, √(3/5)):

f'(√(1/5)) = 45(√(1/5))^4 - 9(√(1/5))² = -18/5 < 0. Decreasing

(√(3/5), ∞): f'(1) = 45(1)^4 - 9(1)² =

36 > 0. Increasing.

Therefore, the function is increasing in the interval

(−∞, -√(3/5)) U (√(3/5), ∞)

And decreasing in the interval

(-√(3/5), 0) U (0, √(3/5))

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3 years ago
Determine the angle of rotation.<br>-165<br>-125<br>125<br>165​
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