Isolate the variable by dividing each side by factors that don't contain the variable.
x  =  1
-6+3x+4=2-4x+3
-8+7x+1=0
7x=7
x=1
 
        
             
        
        
        
Answer:
. JUST LOAD
Step-by-step explanation:
 
        
             
        
        
        
Answer:
Here it is!
Step-by-step explanation:
 
        
             
        
        
        

    so, no breaks on the denominator thus, the LCD will be all three then.
![\bf \cfrac{3}{x-2}+\cfrac{4}{x-1}-\cfrac{1}{x}\implies \cfrac{[3x(x-1)]+[4x(x-2)]-[(x-2)(x-1)]}{x(x-2)(x-1)}
\\\\\\
\cfrac{[3x^2-3x]+[4x^2-8x]-[x^2-3x+2]}{x(x-2)(x-1)}
\\\\\\
\cfrac{3x^2-3x+4x^2-8x-x^2+3x-2}{x(x-2)(x-1)}
\\\\\\
\cfrac{6x^2-8x-2}{x(x-2)(x-1)}\implies \cfrac{2(x^2-4x-1)}{x(x-2)(x-1)}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B3%7D%7Bx-2%7D%2B%5Ccfrac%7B4%7D%7Bx-1%7D-%5Ccfrac%7B1%7D%7Bx%7D%5Cimplies%20%5Ccfrac%7B%5B3x%28x-1%29%5D%2B%5B4x%28x-2%29%5D-%5B%28x-2%29%28x-1%29%5D%7D%7Bx%28x-2%29%28x-1%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B%5B3x%5E2-3x%5D%2B%5B4x%5E2-8x%5D-%5Bx%5E2-3x%2B2%5D%7D%7Bx%28x-2%29%28x-1%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B3x%5E2-3x%2B4x%5E2-8x-x%5E2%2B3x-2%7D%7Bx%28x-2%29%28x-1%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B6x%5E2-8x-2%7D%7Bx%28x-2%29%28x-1%29%7D%5Cimplies%20%5Ccfrac%7B2%28x%5E2-4x-1%29%7D%7Bx%28x-2%29%28x-1%29%7D) 
 
        
             
        
        
        
Answer: b or Rebecca's answer 
Step-by-step explanation: brainlest please