Question:
At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent decrease of water in the tank
Answer:
The percent Decrease of water in the tank is 50%
Step-by-step explanation:
Given:
Initial amount of water in the tank at the noon = 6 cm
amount of water remained in water after several hours = 3 cm
To Find:
The percent decrease =?
Solution:
The percent decrease in the tank
=>
Substituting the values
=>
=>
=>
=> 50
Knowing that all triangles angles add up to 180*:
24* + x + ? = 180*
Knowing the straight line is 180*:
180* - 122* = 58*
The equation then is:
24* + x + 58* = 180*
Then solve for X:
(82* + x) - 82* = (180*) - 82*
<u>x = 98* or C</u>
All you have to do is combine like terms here...all the x's and then all the constants. 2.3x + 2x -.2x = 4.1x; 14 + 15 = 29, so the perimeter is 4.1x + 29, A above.
Answer:
x=√−16n−28 or x=−√−16n−28
Step-by-step explanation:
Step 1: Add -16n to both sides.
x2+16n+28+−16n=0+−16n
x2+28=−16n
Step 2: Add -28 to both sides.
x2+28+−28=−16n+−28
x2=−16n−28
Step 3: Take square root.
x=√−16n−28 or x=−√−16n−28
65+40÷83=1 which would be the least simplest way to solve it but sorry
