Answer:
Cos(F) = 5/13
Sin(F) = 12/13
Tan(F) = 12/5
Step-by-step explanation:
Soh Sine: Opposite(12) over Hypotenuse(13)
Cah Cosine: Adjacent(5) over Hypotenuse(13)
Toa Tangent: Opposite(12) over Adjacent(5)
The correct model of the height of rocket above water is;
h(t) = -16t² + 96t + 112
Answer:
time to reach max height = 3 seconds
h_max = 256 ft
Time to hit the water = 7 seconds
Step-by-step explanation:
We are given height of water above rocket;
h(t) = -16t² + 96t + 112
From labeling quadratic equations, we know that from the equation given, we have;
a = -16 and b = 96 and c = 112
To find the time to reach maximum height, we will use the vertex formula which is; -b/2a
t_max = -96/(2 × -16)
t_max = 3 seconds
Thus, maximum height will be at t = 3 secs
Thus;
h_max = h(3) = -16(3)² + 96(3) + 112
h_max = -144 + 288 + 112
h_max = 256 ft
Time for it to hit the water means that height is zero.
Thus;
-16t² + 96t + 112 = 0
From online quadratic formula, we have;
t = 7 seconds
Answer:
22
Step-by-step explanation:
1.) -2²-9(-2)
2.) -2(-2)+18
3.) 4+18
4.) 22
The answer is in the enclosed diagram
