<u>Answer</u>:
Atoms of every element are shown in a skeletal model of an organic molecule.
<u>Explanation</u>:
Skeletal model of an organic molecule consists of various skeletal atoms that are used in making up of the molecule. Various conventions of hydrogen and carbon atoms are employed in it. The molecules bonding and certain representation of molecular geometry are shown in the structural formula.
Use of skeletal formula is ubiquitous in organic chemistry. Thus, in organic chemistry atoms of every element are shown in the skeletal model of an organic molecule
Answer:
Explanation:
Boyle's Law:
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula when Final temperature is to be calculated,
P₁V₁ = P₂V₂
1.8 atm × 350 L = 1 atm × V₂
V₂ = 630 atm. L/1 atm
V₂ = 630 L
Charles Law:
"The volume of given amount of gas is directly proportional to its temperature by keeping the pressure and number of moles constant"
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
If the three values are given the forth one can be calculated.
For example,
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 4.5 L × 348 K / 298 k
V₂ = 1566 L.K / 298 K
V₂ = 5.3 L
Gay-Lussac's Law:
"The pressure of given amount of gas is directly proportional to its temperature by keeping the volume and number of moles constant"
Mathematical expression:
P₁/T₁ = P₂/T₂
P₁ = Initial pressure
T₁ = Initial temperature
P₂ = Final pressure
T₂ = Final temperature
If the three values are given the forth one can be calculated.
For example,
P₁/T₁ = P₂/T₂
P₂ = P₁T₂/T₁
P₂ = 4.5 atm × 348 K / 298 k
P₂ = 1566 atm.K / 298 K
P₂ = 5.3 atm
According to the second-order rate constant formula:
K t = 1/[At] - 1/[Ao]
when k is the rate constant = 0.035 (given missing in your question)
and t is the time = 190 sec
Ao is the initial concentration of X = 0.35 m
by substitution:
0.035 * 190 sec = 1/[At] - 1/0.35
∴ [At] = 0.11 m
∴ the concentration after 190 sec = 0.11 m