6. Alkali metals, alkaline earth metals, and halogens
2 answers:
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Answer:
1-(tert-butoxy)-2-methylpropane
Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.
Explanation:
<em>Structural formula is attached</em>
IUPAC naming rules
1. start numbering the chain from the functional group. In this compound we start from oxygen side.
2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.
3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.
4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane
5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane
<u>Answer:</u>
<em>Bronsted Lowry Theory</em>
<em> is the acid </em>
<em> is the base </em>
<em> is the conjugate acid and </em>
<em> is the conjugate base</em>
<u>Explanation:</u>
Bronsted Lowry Theory:
An acid is a substance that can donate one or more protons
A base is a substance which can accept one or more protons
Hydrogen atom which is neutral (No Charge) contains 1 positive proton, 1 negative electron and 0 neutral neutron.
Thus Hydrogen atom has no Charge and it is neutral.
When an hydrogen atom loses an electron, Hydrogen ion is formed, which will contain 1 positive proton and 0 negative electron and 0 neutral neutron.
Thus Hydrogen ion has a positive charge.
Hydrogen ion is also called as a proton since it has only 1 proton in it.
Hydrogen ion in water that is,
is called as Hydronium ion.
Acid loses H+ (proton) to form conjugate Base
Base gains H+ (proton) to form conjugate Acid
For example
Let us consider the example given in the question
can be written as (removed 1
from both the sides )
or
reversing the equation
is the acid which donates
to form
is the base which gains
to form
is the conjugate base and
is the conjugate acid
So
is the acid
is the base
is the conjugate acid and
is the conjugate base
(Answer)
