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satela [25.4K]
4 years ago
11

4. I'm the "brain" of the cell or so they say. I regulate activities from day to day...​

Chemistry
1 answer:
Luba_88 [7]4 years ago
6 0

Answer:

nucleus

Explanation:

it holds information needed to regulate most of the cell functions

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Answer:

here you go

Explanation:

someone help me on this but i still got a hundred

5 0
2 years ago
I want to balance S+O2 = SO3
Gre4nikov [31]

Answer:

2S +3O2 =2SO3

Explanation:

2 at the front of sulphur is to equalize the 2 put in SO3.

7 0
3 years ago
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Please help ASAP <br> Read thing for the question thanks!!
katovenus [111]

Answer:

JOSHUA

Explanation:

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4 0
3 years ago
1) How many atoms are in 0.54 moles of Cu? show work ​
mario62 [17]
<h3>Answer:</h3>

3.3 × 10²³ atoms Cu

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 0.54 moles Cu

[Solve] atoms Cu

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 0.54 \ mol \ Cu(\frac{6.022 \cdot 10^{23} \ atoms \ Cu}{1 \ mol \ Cu})
  2. [DA] Multiply [Cancel out units]:                                                                     \displaystyle 3.25188 \cdot 10^{23} \ atoms \ Cu

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.25188 × 10²³ atoms Cu ≈ 3.3 × 10²³ atoms Cu

7 0
3 years ago
If a gas occupies 79.5 mL at -1.4°C, what temperature, in Kelvin, would it
Anna35 [415]

Answer:

121 K

Explanation:

Step 1: Given data

  • Initial volume (V₁): 79.5 mL
  • Initial temperature (T₁): -1.4°C
  • Final volume (V₂): 35.3 mL

Step 2: Convert "-1.4°C" to Kelvin

We will use the following expression.

K = °C + 273.15 = -1.4°C + 273.15 = 271.8 K

Step 3: Calculate the final temperature of the gas (T₂)

Assuming ideal behavior and constant pressure, we can calculate the final temperature of the gas using Charles' law.

V₁/T₁ = V₂/T₂

T₂ = V₂ × T₁/V₁

T₂ = 35.3 mL × 271.8 K/79.5 mL = 121 K

5 0
3 years ago
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