You are given a galvanic cell consists of a Ni²⁺/ Ni half-cell and a standard hydrogen electrode. Also, you are given that the half cell Ni²⁺/ Ni will act as an anode, and the standard cell potential is 0.26V. You are asked to find the standard reduction potential for the half cell Ni²⁺/ Ni.
You will have a half - reaction for both nickel and hydrogen
The conversion of the symbol Ni²⁺/ Ni half-cell is
Ni²⁺ + 2e⁻ → Ni (s) E = 0.26V
and the conversion of the standard hydrogen electrode (SHE) is
2H⁺ + 2e⁻ → H₂ (g) E = 0V
Since H⁺ ions is a it difficult to set up during the process, nickel will be deposited at the cathode side instead of the anode. Therefore, The standard electron potential of the nickel will have -0.26V.
The answer is C) Electrons are not in a fixed position.
Answer:
where the wind is going
Explanation:
direction is where something is going hope it helps
Answer:
Mass = 544 g
Explanation:
Given data:
Mass of sulfuric acid formed = ?
Mass of water react = 100.0 g
Solution:
Chemical equation:
SO₃ + H₂O → H₂SO₄
Number of moles of water:
Number of moles = mass/molar mass
Number of moles = 100 g/ 18 g/mol
Number of moles = 5.5 mol
Now we will compare the moles of water and H₂SO₄.
H₂O : H₂SO₄
1 : 1
5.56 : 5.56
Mass of H₂SO₄:
Mass = number of moles × molar mass
Mass = 5.56 mol × 98.0 g/mol
Mass = 544 g
Answer:
The correct answer is option B, that is, western boundary currents.
Explanation:
The Western boundary currents get deflected by the eastern coastline of the continents. The western boundary currents refer to the deep, warm, narrow, and fast flowing currents, which produce on the west end of the ocean basins because of the western intensification. They conduct warm water from the tropics poleward. Some of the examples of western boundary currents are the Agulhas current, Gulf Stream, and the Kuroshio.