3∅ can be rewritten as (2∅+∅)
sin(3∅) = sin(2∅ + ∅<span>)
Opening brackets on the right hand side;
= sin2</span>∅ cos ∅ + cos2∅sin<span>∅
</span><span>This simplifies to;
= 2sin</span>∅cos^2∅ + sin∅ (1- 2sin^2∅<span>)
= sin</span>∅ (2cos^2∅ + 1 - 2sin^2∅<span>)
= sin</span>∅ (2(1 - sin^2∅) +1-2sin^2∅<span>)
= 3sin</span>∅ - 4sin^3<span>∅</span>
Answer: Is -25/3 or -8.3 repeating.
4 1/2 = 9/2
5/9 x 9/2 = 45/18
You can use the pythagorean theorem.
Now lets write out what we know.
Shorter leg = x
Longer Leg = x + 7
Hypotenuse = x - 7
Now solve for x
x = 28
Since you know x = 28, which is the shorter leg, you can solve for the rest by just plugging in 28 where x is located. For instance, longer let is x + 7 so
28 + 7 = 35
The quadratic is continuous over its entire domain, which is to say we can evaluate the limit by direct substitution:
You are mistaking (-3)² for -3². They are not the same number.
(-3)² = (-1 × 3)² = (-1)² × 3² = 1 × 9 = 9
-3² = -1 × 3² = -1 × 9 = -9