NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

Using the quadratic formula, the solution for our problem is

The rocket splashes after 26.845 seconds.
The maximum of this function happens at the root of the derivative. Differentiating our function, we have

The root is

Then, the maximum height is

1029.99 meters above sea level.
Answer: 628
Step-by-step explanation:
3.14*100*6/3= 628
Answer:
hello : 256 words
Step-by-step explanation:
2 minutes and 30 = (2×60)+30=150seconds
4 minutes = 4 ×60 = 240 seconds
150seconds →160 words
240 seconds → x ?
x = (160×240) / 150 = 38400/150= 256 words
Answer:
The discount% is 15%
Step-by-step explanation:
Given : The price of a sweater was slashed from Rs 960 to Rs 816 by a shopkeeper in the winter season.
To find : The rate of discount given by him?
Solution :
According to question,
The market price of the sweater is Rs.960
The selling price of the sweater is Rs.816
The discount on the sweater is given bY
Discount % is given by
Therefore, The discount% is 15%.