Answer:
9x^2(5y^2 + 2x).
Step-by-step explanation:
First find the Greatest Common Factor of the 2 terms.
GCF of 18 and 45 = 9
GCF of x^2 and x^3 = x^2.
The complete GCF is therefore 9x^2.
So, dividing each term by the GCF, we obtain:
9x^2(5y^2 + 2x).
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5: Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
The elevations of four points below sea level are -47 feet, -24 feet, -8 feet, and -18 feet.
The elevation of the point closest to sea level is feet
-8 ft
elevation of the point farthest from sea level is feet.
-47 ft
closet to sea level to farthest to sea level
-8ft , -18ft , -24ft , -47ft
<u>Part 1)</u> "Four times the difference of a number and
is
"
Let
x--------> the number
we know that
the expressions is equal to

therefore
<u>the answer part 1) is</u>

<u>Part 2)</u> "One third of a number is
less than the number itself"
Let
x--------> the number
we know that
the expressions is equal to

therefore
<u>the answer part 2) is</u>

<u>Part 3)</u> "Ten increased by the quotient of a number and
is
"
Let
x---------> the number
we know that
the expressions is equal to

therefore
<u>the answer Part 3) is</u>

<u>Part 4)</u> "One less than the product of a number and
is
more than the number itself"
Let
x---------> the number
we know that
the expressions is equal to

therefore
<u>the answer Part 4) is</u>

Answer:
The number of solutions is one
Step-by-step explanation:
Here, we want to get the number of solutions
since the linear equations are not the same, neither do they have the same x-variable, we can have only one solution