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3 years ago

What is the theoretical probability a fair coin will land on tails?

Mathematics

1 answer:

Harman [31]3 years ago

5 0

There are two sides in a coin so the chance of getting tails is 1/2, which would be 0.5.

I'm not sure tho.

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Help me on this please

Vitek1552 [10]

Right triangle = Pythagoras theorem.
a^2+b^2=c^2
there's already c and b so
10^2-8^2=a^2
100-64= 36
a^2=36
square root both sides
to get 6.

5 0

3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OleMash [197]

Answer:

Option C it is sure

4 0

3 years ago

Read 2 more answers

3+m+4≤5 please help due tommorow

ruslelena [56]

$3+m+4 \leq 5 \\\\ m+7 \leq 5 \\\\ m \leq 5-7 \\\\ m \leq -2 \\\\ \boxed{m=(-\infty;-2]}$

7 0

4 years ago

Read 2 more answers

Last year your school had 1200 students enrolled, this year your school has135% of that amount enrolled. how many students are e

iren2701 [21]

1200 = 100%
35% of 1200 = 420
1200 + 420 = 1620

There are 1620 students enrolled this year.

7 0

3 years ago

Factor the expression completely.

evablogger [386]

Answer:

Factoring the expression $xy^4+x^4y^4$ completely we get $\mathbf{xy^4(x+1)(x^2-x+1)}$

Step-by-step explanation:

We need to factor the expression $xy^4+x^4y^4$ completely

We need to find common terms in the expression.

Looking at the expression, we get $xy^4$ is common in both terms, so we can write:

$xy^4+x^4y^4\\=xy^4(1+x^3)$

So, taking out the common expression we get: $xy^4(1+x^3)$

Now, we can factor the term (1+x^3) or we can write (x^3+1) by using formula:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

So, we get:

$xy^4(1+x^3)\\=xy^4(x^3+1)\\Applying\:the\:formula\;of\:a^3+b^3\\=xy^4(x+1)(x^2-x+1)$

Therefor factoring the expression $xy^4+x^4y^4$ completely we get $\mathbf{xy^4(x+1)(x^2-x+1)}$

6 0

3 years ago