When the density formula at STP is:
density = molar mass / molar volume
So we can get the molar mass of SO3 from the periodic table = 32 + (16x3) = 80g
and at STP each 1 mole of gas occupy 22.4 L so we have the molar volume at STP = 22.4.
So by substitution in the density formula:
∴ density of SO3 = 80 g / 22.4 L = 3.571 g /L
Answer:
300 centavos
Explanation:
De la pregunta anterior, se obtuvieron los siguientes datos:
Potencia (P) = 2500 W
Tiempo (t) = 8 horas
Costo de operación =?
A continuación, convertiremos 2500 W a KW. Esto se puede obtener de la siguiente manera:
1000 W = 1 KW
Por lo tanto,
2500 W = 2500 W × 1 KW / 1000 W
2500 W = 2,5 KW
Por tanto, 2500 W equivalen a 2,5 KW
A continuación, determinaremos la energía consumida. Esto se puede obtener de la siguiente manera: Potencia (P) = 2,5 KW
Tiempo (t) = 8 horas
Energía (E) =?
E = Pt
E = 2,5 × 8
E = 20 KWh
Finalmente, determinaremos el costo de operación. Esto se puede obtener de la siguiente manera:
1 KWh = 15 centavos
Por lo tanto,
20 KWh = 20 KWh × 15 centavos / 1 KWh
20 KWh = 300 centavos
Por lo tanto, costará 300 centavos tener un radiador de 2500 W encendido toda la noche (8 horas).
Answer:
20 ounces of 14% solution and 8 ounces of 7% solution.
Explanation:
Let the amount of 14% solution required be A and the amount of 7% solution required be B.
Mixture of A and B must give 28 ounces:
A + B = 28 ................. Eqn 1
Also, mixture of 14% A and 7% B must give 12%, 28 ounces solution:
0.14A + 0.07B = 0.12(28) = 3.36...................Eqn 2
From eqn 1, B = 28 - A, eqn 2 becomes:
0.14A + 0.07(28 - A) = 3.36
0.07A = 3.36 - 1.96
A = 20 ounces
Substitute the value of A into eqn 1 to get B:
20 + B = 28
B = 8 ounces.
Hence, 20 ounces of 14% hydrochloric acid and 8 ounces of 7% hydrochoric acid should be mixed together in order to get 28 ounces of 12% solution.
Answer:
wind..........................
Answer:
By recycling and cleaning up there community.
Explanation:
