Answer:
648.68 mg
Explanation:
The reaction that takes place is:
- FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl
First we<u> calculate how many moles of each reactant were added</u>, using the <em>given volumes and concentrations</em>:
- FeCl₃ ⇒ 100 mL * 0.240 M = 24 mmol FeCl₃
- NaOH ⇒ 100 mL * 0.182 M = 18.2 mmol NaOH
24 mmol of FeCl₃ would react completely with (24 * 3) 72 mmol of NaOH. There are not as many NaOH mmoles, so NaOH is the limiting reactant.
Now we <u>calculate how many moles of Fe(OH)₃ are formed</u>, using the <em>moles of the limiting reactant</em>:
- 18.2 mmol NaOH *
= 6.07 mmol Fe(OH)₃
Finally we <u>convert 6.07 mmol Fe(OH)₃ to grams</u>, using its<em> molar mass</em>:
- 6.07 mmol Fe(OH)₃ * 106.867 mg/mmol = 648.68 mg