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frez [133]
2 years ago
10

What are some ways that students and staff of a school can help slow water, land, and air pollution?

Chemistry
2 answers:
Nata [24]2 years ago
6 0

Answer:

By recycling and cleaning up there community.

Explanation:

s2008m [1.1K]2 years ago
3 0
By turning off the tap when they are soaping there hands , washing only necessary needs
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Magnesium hydroxide is used as an antacid in milk of magnesia and reacts with hydrogen chlrode in the stomach to form water and
8_murik_8 [283]
Mg(OH)2 +2HCl---> MgCl2+2H2O
3 0
3 years ago
A board measures 212 inches. How many feet is this?
quester [9]
17.6667 Feet is the answer.
6 0
3 years ago
Read 2 more answers
What is the theoretical yield of aluminum oxide if 3.00 mol of aluminum metal is exposed to 2.55 mol of oxygen?
lisabon 2012 [21]

Theoretical yield of Al₂O₃: 1.50 mol.

<h3>Explanation</h3>

2 \; \text{Al} + \dfrac{3}{2} \; \text{O}_2 \to {\bf 1} \; \text{Al}_2\text{O}_3;

4 \; \text{Al} + 3 \; \text{O}_2 \to 2 \; \text{Al}_2\text{O}_3 \; \textit{Balanced}.

How many moles of aluminum oxide formula units will be produced <em>if</em> aluminum is the limiting reactant?

Aluminum reacts to aluminum oxide at a two-to-one ratio.

3.00 \times \dfrac{1}{2} = 1.50 \; \text{mol}.

As a result, 3.00 moles of aluminum will give rise to 1.50 moles of aluminum oxide.

How many moles of aluminum oxide formula units will be produced <em>if</em> oxygen is the limiting reactant?

Oxygen reacts to produce aluminum oxide at a three-to-two ratio.

2.55 \times \dfrac{2}{3} = 1.70 \; \text{mol}

As a result, 2.55 moles of oxygen will give rise to 1.70 moles of aluminum oxide.

How many moles of aluminum oxide formula units will be produced?

Aluminum is the limiting reactant. Only 1.50 moles of aluminum oxide formula units will be produced. 1.70 moles isn't feasible since aluminum would run out by the time 1.50 moles was produced.

4 0
3 years ago
Red #40 has an acute oral LD50 of roughly 5000 mg dye/1 kg body weight. This means if you had a mass of 1 kg, ingesting 5000 mg
FrozenT [24]

Answer:

350 g dye

0.705 mol

2.9 × 10⁴ L

Explanation:

The lethal dose 50 (LD50) for the dye is 5000 mg dye/ 1 kg body weight. The amount of dye that would be needed to reach the LD50 of a 70 kg person is:

70 kg body weight × (5000 mg dye/ 1 kg body weight) = 3.5 × 10⁵ mg dye = 350 g dye

The molar mass of the dye is 496.42 g/mol. The moles represented by 350 g are:

350 g × (1 mol / 496.42 g) = 0.705 mol

The concentration of Red #40 dye in a sports drink is around 12 mg/L. The volume of drink required to achieve this mass of the dye is:

3.5 × 10⁵ mg × (1 L / 12 mg) = 2.9 × 10⁴ L

8 0
3 years ago
When you stand on a bathroom scale, what force or forces are acting on you?
Readme [11.4K]

Answer:

B

Explanation:

Lets see here, Gravity is pulling you down but your body is repelling to gravity. Meaning that gravity is pulling down your weight and the scale is reading it.

Hope this helped!

3 0
2 years ago
Read 2 more answers
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