Two sets (or three technically)
sets {2, 4, 6, 8, 10} & {8,9,10}
The probability of one of the above numbers because it is a union of those two vars/sets so numbers from either set go
{2, 4, 6, 8, 9, 10}
Thats 6 of the 10 numbers
6/10
.6
If i'm wrong, sorry, haven't done this kind of stuff in a while
<span>the answer is 21 if that's a choice
</span><span>
</span>
Answer:
263
Step-by-step explanation:
take the start amount 315 and subtract 78 then add 26 which would amount to 263
The answer to this question is 0
