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zimovet [89]
3 years ago
8

The pair of shoes you want is on sale for 25% off. If the shoes originally cost $65, how much is the sale price

Mathematics
2 answers:
natima [27]3 years ago
8 0
I think it’s $48.75 because 25% off of $65 is $16.25 and then $48.75-$16.25=$48.75
Ludmilka [50]3 years ago
5 0
$48.75
Good this help. Ask if you want me to explain :)
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Plz help with this question and explain
alekssr [168]
I see two lines. The degree measure of any line is 180°.

4y + 5y = 180°

9y = 180°

y = 180°/9

y = 20
5 0
3 years ago
Please please please help!!!!
RUDIKE [14]

Answer:

only -3,5 is the answer.

6 0
2 years ago
Find the area of the shape shown below.
maw [93]

Answer:

The area is 28.

Step-by-step explanation:

Visualize the rectangle as 2 split squares.

The top square is easily 4x4, so the area of that part is 16.

Now visualize the bottom square as two rectangles.

To find the area of the dented side, you would use the equation of finding the area of a triangle, a=(w x h)\frac{1}{2} because the dented side is actually just one half of the rectangle on the other side.

Since it is the same height as the top square, but is 2 in width, it would be written as a=(2 x 4)\frac{1}{2} . So the area of that part is 4, and the area of the other rectangle would be just 2 x 4 so it is 8.

Totaling these numbers, you get the area of the full rectangle.

8 0
3 years ago
Read 2 more answers
Which of the following represents a number squared is equal to twenty more than nine times that number ?
Neko [114]

Answer:

I believe it's B

Step-by-step explanation:

5 0
3 years ago
Use the standard normal distribution or the​ t-distribution to construct a 99​% confidence interval for the population mean. Jus
vichka [17]

Answer:

(25.732,30.868)

Step-by-step explanation:

Given that in a random sample of 42 ​people, the mean body mass index​ (BMI) was 28.3 and the standard deviation was 6.09.

Since only sample std deviation is known we can use only t distribution

Std error = \frac{s}{\sqrt{n} } =\frac{6.09}{\sqrt{42} } \\=0.9397

df = 42-1 =41

t critical for 99% two tailed = 2.733

Margin of error= 2.733*0.9397=2.568

Confidence interval lower bound = 28.3-2.568=25.732

Upper bound = 28.3+2.568=30.868

3 0
3 years ago
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