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3 years ago

The pair of shoes you want is on sale for 25% off. If the shoes originally cost $65, how much is the sale price

Mathematics

2 answers:

natima [27]3 years ago

8 0

I think it’s $48.75 because 25% off of $65 is $16.25 and then $48.75-$16.25=$48.75

Ludmilka [50]3 years ago

5 0

$48.75
Good this help. Ask if you want me to explain :)

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HELP URGENT BRAINLIEST

nadya68 [22]

Given:

LMN is an equilateral triangle.

LM = LN = MN = 12 cm

To find:

The height of the triangle h.

Solution:

In a right angle triangle,

$\sin \theta=\dfrac{Opposite}{Hypotenuse}$

$\sin (60^\circ)=\dfrac{h}{12}$

$\dfrac{\sqrt{3}}{2}=\dfrac{h}{12}$

Multiply both sides by 12.

$\dfrac{\sqrt{3}}{2}\times 12=\dfrac{h}{12}\times 12$

$6\sqrt{3}=h$

Therefore, the height of the triangle is $6\sqrt{3}$ cm.

3 0

3 years ago

I need the answer fast please

shusha [124]

The diameter of the circle is needed. But to solve, you would simply multiply the diameter of the circle by pi (3.14).

3 0

3 years ago

What are the equations of lines m and q? Please

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

3 0

3 years ago

Steve connected a wire extension that is 3/8 foot long to another wire that is 1/2 foot long. How long is the wire with the exte

hammer [34]

Answer:

<u>7/8 feet</u>

Step-by-step explanation:

In order to add two frctions you need to make their denominator the same,

3/8 can be kept as it is and we can multiply the top and bottom of 1/2 by 4 in order to ger 4/8. Now it is easier to add together,

3/8 + 4/8= <u>7/8</u>

6 0

3 years ago

The Carousel at Carowinds has 4 rings of horses. Fred is riding on the inner ring, which has a radius of 7 feet. Juan is riding

nikdorinn [45]

Answer:

Juan travel 31.4 feet farther than Fred in one rotation.

Step-by-step explanation:

In this problem we need to determine the change in linear position of Fred and Juan, whose formula is:

$s=\theta \cdot r$ (Eq. 1)

Where:

$r$ - Radius, measured in feet.

$\theta$ - Angular arch, measured in radians.

$s$ - Change in linear position, measured in feet.

If both makes one rotation in the carousel, we obtain the change in linear position of each player:

Fred ( $r = 7\,ft$ , $\theta = 2\pi$ )

$s= 2\pi\cdot (7\,ft)$

$s = (3.14)\cdot (7\,ft)$

$s = 21.98\,ft$

Juan ( $r = 17\,ft$ , $\theta = 2\pi$ )

$s= 2\pi\cdot (17\,ft)$

$s = (3.14)\cdot (17\,ft)$

$s = 53.38\,ft$

And the difference between both travelled distances is:

$\Delta s = 53.38\,ft-21.98\,ft$

$\Delta s = 31.4\,ft$

Juan travel 31.4 feet farther than Fred in one rotation.

4 0

3 years ago