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pogonyaev
3 years ago
14

A car starts moving at 9:00 am and moves at a constant speed. At what time will the car be at the distance 200 miles from the st

arting point, if at 9:30 it was at 20 miles from it.
Mathematics
2 answers:
Katarina [22]3 years ago
7 0

Answer:

1:30

Step-by-step explanation:

This is correct

andriy [413]3 years ago
6 0

. i got the answer of 2:00

Step-by-step explanation:

yea

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Soloha48 [4]

✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽

➷ 30 + 17

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4 0
3 years ago
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chris can run at a constant speed of 12 km/h. How ling will it take him to run from his home to the park, a distance of 0.8 km?
densk [106]

Recall that distance = speed times time. Thus, time = distance / speed.

Here:

time = distance / speed = 0.8 km / 12 km/hr = 1/15 hr.

Note that 1/15 hr = 1/15 (60 min) = 4 minutes

8 0
3 years ago
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F(x) = x^2 - 3x+ 5 g(x) = 2x^2 - 4x - 11 what is h(x) = f(x) + g(x)
iogann1982 [59]

Hey there! :)

Answer:

h(x) = 3x² - 7x - 6

Step-by-step explanation:

Calculate h(x) by adding the two polynomials:

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h(x) = x² - 3x + 5 + 2x² - 4x - 11

Combine like terms:

h(x) = 3x² - 7x - 6

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3 years ago
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* Let S = Span {(2,-1, 1), (3, 1, 1), (1, 2, 0)}. (i) Calculate the dimension of S.
Sholpan [36]

The span of 3 vectors can have dimension at most 3, so 9 is certainly not correct.

Check whether the 3 vectors are linearly independent. If they are not, then there is some choice of scalars c_1,c_2,c_3 (not all zero) such that

c_1 (2,-1,1) + c_2 (3,1,1) + c_3 (1,2,0) = (0,0,0)

which leads to the system of linear equations,

\begin{cases} 2c_1 + 3c_2 + c_3 = 0 \\ -c_1 + c_2 + 2c_3 = 0 \\ c_1 + c_2 = 0 \end{cases}

From the third equation, we have c_1=-c_2, and substituting this into the second equation gives

-c_1 + c_2 + 2c_3 = 2c_2 + 2c_3 = 0 \implies c_2 + c_3 = 0 \implies c_2 = -c_3

and in turn, c_1=c_3. Substituting these into the first equation gives

2c_1 + 3c_2 + c_3 = 2c_3 - 3c_3 + c_3 = 0 \implies 0=0

which tells us that any value of c_3 will work. If c_3 = t, then c_1=t and c_2 = -t. Therefore the 3 vectors are not linearly independent, so their span cannot have dimension 3.

Repeating the calculations above while taking only 2 of the given vectors at a time, we see that they are pairwise linearly independent, so the span of each pair has dimension 2. This means the span of all 3 vectors taken at once must be 2.

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2 years ago
Help me please i would really appreciate it ill give 20+ points
Alinara [238K]
It might be d because the side are all the exact same size!
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3 years ago
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