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vekshin1
2 years ago
11

Delta math help please

Mathematics
1 answer:
natta225 [31]2 years ago
7 0
<h3>Given,</h3>

2y {}^{2}  + 9y + 2

Value of y = 7

Therefore Value Of Whole Expression=

2 \times (7) {}^{2}  + 9 \times 7 + 2 \\  \\  = 2 \times 49 + 63 + 2 \\  \\ =  98 + 63 + 2 \\  \\ =  163

<h3>Hope This Helps You</h3>
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7 times what gives me 36
Zolol [24]
To get the answer, divide 36 by 7. And the answer of that is 5.1428571428571429
8 0
2 years ago
List the steps to solve this
miskamm [114]

Answer:

Step-by-step explanation:

First, distribute the 2 to the 3z and -6 within the parenthesis.

You know have 6z -12/5 + 6 = 10

Subtract 6 from both sides of the equation

6z -12/5 = 4

Multiply 5 on both sides of the equation

6z -12 = 20

Add 12 to both sides of the equation

6z = 32

Divide by 6 on both sides of the equation

z = 32/6

Simplify

z = 16/3

I hope that this helps! :)

5 0
3 years ago
find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation. if y
dlinn [17]

Answer:

The Question isn't clear

Step-by-step explanation:

7 0
2 years ago
To which real number sets does the number 13 belong?
Crazy boy [7]
13 is a whole number, integer, natural number and rational number. Rational number because it can be written as a fraction like 13/1. It is a whole number because it doesn't have any decimals. It is an integer because an integer is a positive or negative whole number and it is a natural number because a natural number is any positive number greater than 0.
3 0
3 years ago
−4x+7y+5=0<br> x−3y=−5<br> ​ <br><br> How many solutions does the system have?
xeze [42]

   

Solution:  

Using Substitution Method:

-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

get the value of x from Equation 2

x=3y-5     (Equation 3)  

Put the value of x from Equation 3 in Equation 1

-4(3y-5)+7y=-5

-4(3y)+20+7y=-5

-12y+7y=-5-20

-5y=-25

Negative sign on both sides cancels each other

y=25/5

y=5

Putting value of y in equation 3

x=3(5)-5

x=15-5

x=10

Therefore,   [x,y]=[10,5]

Using Elimination Method

-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

Multiply equation 2 with -4 in order to eliminate the x term

-4(x-3y)=-5*4

-4x+12y=20     (Equation 3)

Adding Equation 1 and 3

-4x+7y=-5    

-4x+12y=20    

+    -     = -   (Change Of Sign with x and y terms)

-----------------

0x-5y = -25

-5y=-25

y=5  

Substituting y’s value is Equation 1

-4x+7(5)=-5

-4x+35=-5

-4x=-40

Cancellation of negative sign on both sides

x=40/4

x=10

[x,y]=[10,5]

3 0
2 years ago
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