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3 years ago

When the balloon touched the wall, it stayed there. What is the best explanation for the balloon staying on the wall?

Mathematics

1 answer:

Aneli [31]3 years ago

7 0

Answer:

When the negatively charged balloon approaches a wall, the negative charges in the wall are repelled (or pushed away)

Step-by-step explanation:

As the two come in contact, the balloon will stick because of the rule that opposites attract (positive to negative)

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4 years ago

Point C is located at (1, 2) and point D is located at (−4, −2). Find the x value for the point that is 1 over 4 the distance fr

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Answer:

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Step-by-step explanation:

Coordinates of C = $(x_{1} ,y_{1} )=(1,2)$

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Let Coordinates of A= (x,y)

Since A point is located 1/4 the distance from C to D

So the remaining distance from point A to D is 3/4

Thus the ratio of CA : AD = m:n=1:3

Now to find points of A we will use section formula i.e.

$x=\frac{mx_{2}+nx_{1}}{m+n}$

$y=\frac{my_{2}+ny_{1}}{m+n}$

Substituting the values:

$x=\frac{1*-4+3*1}{1+3}$

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Hence option a is correct

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3 years ago

When the balloon touched the wall, it stayed there. What is the best explanation for the balloon staying on the wall? ​

When the balloon touched the wall, it stayed there. What is the best explanation for the balloon staying on the wall?