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2 years ago

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ASAP there are three marbles in a bag. One is red and two are black. What is the probability of picking a black marble first, pu

tting it back in the bag and then picking a black marble? Use the following probability to find the answer.

2 answers:

FrozenT [24]2 years ago

6 0

Answer:

$\frac{4}{9}$

Step-by-step explanation:

$p = \frac{favorable \: outcomes}{total \: outcomes} = \frac{4}{9}$

Marina86 [1]2 years ago

6 0

<h3>Answer: Choice D) 4/9</h3>

=============================================================

Explanation:

The probability you get a black marble on the first selection is 2/3 since we have 2 black marbles out of 2+1 = 3 total.

We put the marble back and then we have 2/3 as the probability of selecting another black marble on the second try. Nothing has changed because we put the marble back. That means the events are independent.

So we get (2/3)*(2/3) = 4/9 as the probability of selecting 2 black marbles in a row (with replacement).

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Laila and Bryson are finding the slope of a line that passes through the two points (3, -5) and (-4, -6). Who is correct and why

snow_tiger [21]

Slope formular = (y2-y1)/(x2 - x1)
so
slope = (-6 +5)/(-4-3)
slope = -1/-7
slope = 1/7

answer
Laila is correct

3 0

3 years ago

What is the slope of a line whose graph contains the points (−2,−6)<br><br> and (0,0)<br><br>?

torisob [31]

Answer:

It’s D

Step-by-step explanation:

4 0

2 years ago

One year had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at

lord [1]

Answer:

Thomas had the better year relative to their peers.

Step-by-step explanation:

<u>The complete question is</u>: One year Thomas had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 3.31. Also, Karla had the lowest ERA of any female pitcher at the school with an ERA of 3.02. For the males, the mean ERA was 4.837 and the standard deviation was 0.541. For the females, the mean ERA was 4.533 and the standard deviation was 0.539. Find their respective z-scores. Which player had the better year relative to their peers, or ? (Note: In general, the lower the ERA, the better the pitcher.)

We are given that for the males, the mean ERA was 4.837 and the standard deviation was 0.541. For the females, the mean ERA was 4.533 and the standard deviation was 0.539.

As, we know that the z-score is calculated by the following formula;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean

$\sigma$ = standard deviation

Now, firstly we will calculate the z score for Thomas;

z-score = $\frac{X-\mu}{\sigma}$

= $\frac{3.31-4.837}{0.541}$ = -2.823

{Here, the mean ERA for the males was 4.837 and the standard deviation was 0.541}

Similarly, we will calculate the z score for Karla;

z-score = $\frac{X-\mu}{\sigma}$

= $\frac{3.02-4.533}{0.539}$ = -2.807

{Here, the mean ERA for the females was 4.533 and the standard deviation was 0.539}

Now, it is stated in the question that the lower the ERA, the better the pitcher.

So, we can clearly see that Thomas had a lower ERA of z-score as -2.823 < -2.807. This means that Thomas had the better year relative to their peers.

5 0

2 years ago

An experiment involves flipping a coin three times.

Xelga [282]

Answer:

19/50

Step-by-step explanation:

If you put this in decimal form, it's 0.38.

All you have to do is convert the decimal to a reduced fraction, which is 19 over 50 (19/15).

Hope this helps you!

3 0

1 year ago

PLEASE SOLVE QUESTION 13 AND 14 <br>DONT STEAL THE POINTS

Varvara68 [4.7K]

Answer:

See below for solution.

Step-by-step explanation:

$Q13)$ $\frac{\sqrt{11} - \sqrt{5} }{\sqrt{11}+\sqrt{5} }$ = $x - y\sqrt{55}$

<u>LHS :-</u>

= $\frac{\sqrt{11} - \sqrt{5} (\sqrt{11}-\sqrt{5}) }{\sqrt{11}+\sqrt{5} (\sqrt{11}-\sqrt{5}) }$

= $\frac{11-2\sqrt{55}+5 }{11 - 5}$

= $\frac{16-2\sqrt{55} }{6}$

= $\frac{2(8-\sqrt{55}) }{2(3)}$

= $\frac{8-\sqrt{55} }{3}$

=> x = 8/3 and y = 1/3

=> <u>Option B</u>

<u></u>

<u></u> $Q14)$ $\frac{4}{216^{-2/3} }$ + $\frac{1}{256^{-3/4} }$ + $\frac{2}{243^{-1/5} }$

= 4 x (∛216)² + ( $\sqrt[4]256}$ )³ + 2 x ( $\sqrt[5]{243}$ )

= 4 x 36 + 64 + 2 x 3

= 144 + 64 +6

= 144 + 70

= <u>214</u>

3 0

2 years ago