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raketka [301]
3 years ago
14

ASAP there are three marbles in a bag. One is red and two are black. What is the probability of picking a black marble first, pu

tting it back in the bag and then picking a black marble? Use the following probability to find the answer.

Mathematics
2 answers:
FrozenT [24]3 years ago
6 0

Answer:

\frac{4}{9}

Step-by-step explanation:

p =  \frac{favorable \: outcomes}{total \: outcomes}  =  \frac{4}{9}

Marina86 [1]3 years ago
6 0
<h3>Answer:  Choice D)  4/9</h3>

=============================================================

Explanation:

The probability you get a black marble on the first selection is 2/3 since we have 2 black marbles out of 2+1 = 3 total.

We put the marble back and then we have 2/3 as the probability of selecting another black marble on the second try. Nothing has changed because we put the marble back. That means the events are independent.

So we get (2/3)*(2/3) = 4/9 as the probability of selecting 2 black marbles in a row (with replacement).

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