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raketka [301]
3 years ago
14

ASAP there are three marbles in a bag. One is red and two are black. What is the probability of picking a black marble first, pu

tting it back in the bag and then picking a black marble? Use the following probability to find the answer.

Mathematics
2 answers:
FrozenT [24]3 years ago
6 0

Answer:

\frac{4}{9}

Step-by-step explanation:

p =  \frac{favorable \: outcomes}{total \: outcomes}  =  \frac{4}{9}

Marina86 [1]3 years ago
6 0
<h3>Answer:  Choice D)  4/9</h3>

=============================================================

Explanation:

The probability you get a black marble on the first selection is 2/3 since we have 2 black marbles out of 2+1 = 3 total.

We put the marble back and then we have 2/3 as the probability of selecting another black marble on the second try. Nothing has changed because we put the marble back. That means the events are independent.

So we get (2/3)*(2/3) = 4/9 as the probability of selecting 2 black marbles in a row (with replacement).

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2+46×8÷2= can someone find the answer
Dafna1 [17]

Answer:

186

Step-by-step explanation:

PEMDAS

First do 46 x 8 = 368 then divide that by 2, which would be, 184. Then add 2 to 184 and you get 186. :)

6 0
2 years ago
Astrid is in charge of building a new fleet of ships. Each ship requires 40 tons of wood, and accommodates 300 sailors. She rece
Elena L [17]

Answer: 280 tons

Step-by-step explanation: divide all at tons/pound which accumulated to 280 tons

7 0
3 years ago
The manufacturer of a CD player has found that the revenue R​ (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com
AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

R(p) = -5p^2 + 1550p

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550

Equating the first derivative to zero, we get,

\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155

Again differentiation R(p), with respect to p, we get,

\dfrac{d^2(R(p))}{dp^2} = -10

At p = 155

\dfrac{d^2(R(p))}{dp^2} < 0

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

R(155) = -5(155)^2 + 1550(155) = 120125

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0
3 years ago
Patel bought a model rocket kit from a catalog. The
tankabanditka [31]

Answer:

7 weeks

Step-by-step explanation:

add 10 to 125 then divide by 20

5 0
3 years ago
Read 2 more answers
Rihanna
Daniel [21]
The answer to your question is 71%
7 0
3 years ago
Read 2 more answers
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