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Bond [772]
3 years ago
5

State the number of complex roots, the possible number of real, roots, and the number of possible rational roots of...

Mathematics
1 answer:
salantis [7]3 years ago
5 0

Answer:

4

Step-by-step explanation:

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Sketch the analogue of the trace-determinant plane in the bk-plane
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Question Consider, The motion of a a damped harmonic oscillator is described by x′′ x ″ + bx′ b x ′ + kx=0 k x = 0 , where b is greater than or equal to 0 A) Rewrite as a two dimensional linear system. x′=y x ′ = y y′ y ′ = - (by+kx) ( b y + k x ) B) Sketch the analogue of the trace-determinant plane in the bk-plane. That is, identify the regions in the relevant portion of the bk-plane where the corresponding system has similar phase portraits. I have cut out most of my answer etc as it seems to of merely confused people, how does one answer this question?
5 0
3 years ago
Plz help me or I will get my phone taken away
LUCKY_DIMON [66]
I believe it’s 18 because you find 5 then another 4 which is 9 and you guys already had 9, 9 plus 9 equal 18
3 0
3 years ago
Read 2 more answers
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

        199

        175

        ----

          24

         ----

last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

7 0
3 years ago
Can someone help me ?!
True [87]

Answer:

y<-2x-3

Step-by-step explanation:

Your first step is to find the equation of the line. You can see that the y-intercept is -3, therefore your b is -3. So now your formula looks like this:

y=mx-3

To find m, you substitute in an x value and its corresponding y value. When you do this you will get -2.

Now it looks like this:

y=-2x-3.

Now that you have the equation of the line, you can look at the inequality. Since the line is dotted, that means it is not included in the inequality. That mean it cannot contain an equal to. So the only options we have are < and >. Since the shaded area is to the left, which is the negative side, we can conclude that y<-2x-3 is the correct equation.

HOPE THAT THIS IS HELPFUL!

5 0
3 years ago
Which must be true select three options
tatiyna
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8 0
2 years ago
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