Answer:
Initial velocity will be 1.356 m/sec
Explanation:
Let the initial speed = u
Angle at which rubber band is launched = 37°
Horizontal component of initial velocity ![u_x=ucos\Theta =ucos37^{\circ}=0.7986u](https://tex.z-dn.net/?f=u_x%3Ducos%5CTheta%20%3Ducos37%5E%7B%5Ccirc%7D%3D0.7986u)
Time is given as t = 1.20 sec
Distance in horizontal direction = 1.30 m
We know that distance = speed × time
So time ![t=\frac{distance}{speed}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bdistance%7D%7Bspeed%7D)
![1.20=\frac{1.3}{0.7986u}](https://tex.z-dn.net/?f=1.20%3D%5Cfrac%7B1.3%7D%7B0.7986u%7D)
![u=1.356m/sec](https://tex.z-dn.net/?f=u%3D1.356m%2Fsec)
So initial velocity will be 1.356 m/sec
Answer:
aw why? are you deleting the app for school?
first is gamma Ray's, last is d
Answer:
The answer is below
Explanation:
The acceleration of a ball rolling down an inclined plane would be greater than that of the acceleration of a ball rolling up if acted upon by a force of equal magnitude. For a ball rolling down an inclined plane, the acceleration due to gravity (gsinθ) acts in the direction of motion of the ball thereby leading to an increase in the acceleration of the ball; while for a balling rolling upwards, the acceleration due to gravity acts in the direction opposite to the motion of the ball thereby leading to a decrease in the acceleration of the ball.
Answer:
v = 1.36 cm / y
Explanation:
For this exercise we must assume that the displacement of the plates is constant over time, so we will use the kinematic relationships for the uniform movement
v = d / t
We reduce the quantities to the SI system
d = 320 km (1000 m / 1km) (100 cm / 1 m)
d = 3.2 107 cm
let's calculate
v = 32.107 / 23.5 106
v = 1.36 cm / y