Depends on its<span> mass and </span>its<span> speed.</span>
Answer:
A certain battery can power a 100 Ohm-resistance device for 4 hours. How long can the battery power a 200 Ohm device? Ans: 8 ohms
Part B)
If you put two of these batteries in series with each other - still powering a device with the original 100 Ohm resistance - how long would the batteries last? (Note: you have two batteries now, so twice the energy to begin with than with one battery.)
t₁=8hr
t₂=2hr
Explanation:
Given that,
R₁ =100Ω
R₂ =200Ω
t₁ =4hr
Part A
The expression for energy dessipated across a resistor when it is connected with a single resistor (R) is
Here V is the voltage across the source, t is time
energy dissipated across 200ohms is the same as energy dissipated across 100ohms
rearrange the above equation t₂
Part b
Now two batteries are in series
total emf =2V
use the equation below
Answer:
Stress = 4.67 * 10^-7 N/m²
Explanation:
Young's modulus of the material = Stress/Strain
Given
Young's modulus = 228 x 10^9 Pa
Stress = 106,483 Pa
Required
Strain
From the formula;
Strain = Stress/Young modulus
Strain = 106,483 /228 x 10^9
Stress = 4.67 * 10^-7 N/m²
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In energy transfer, happens from one object to another without changing its form. For example, when you fill a pot of water and sit it on the stove, the water continues to heat until you turn it off. While in a energy transformation, the energy changes forms such as Chemical, kinetic.
You must apply Archimides' principle.
The barge will sink until the sum of the forces on it equals zero.
The two forces are the weight of the barge (with sand) and the buoyancy force, the force exerted by the liquid (fresh water) on the barge.
Then, weight of the barge with sand = m*g = 600 kg * g
Buoyancy force = density of the fluid * Volume of displaced fulid * g
Then, m*g = density of the fulid * Volume of displaced fluid * g
m*g = df * Vf * g
m = df*Vf => Vf = m/df = 600 kg / 1 000 kg/m^3 = 0.6 m^3
The volume of the displaced fluid equals the volume of the portion of the barge sinked, wich is the area of the rectangular base times the depth to which it sinked>
7m*2m*H = 0.6 m^3 => H = 0.6 m^3 /[14 m^2] = 0.043 m = 4.3 cm
Answer: 4.3 cm