This is for the reason that individuals are not continually taking a gander at precisely the same, and on the grounds that individuals' psyches of ten work distinctively and process data in marginally extraordinary ways getting diverse understandings of similar information.

7 0

3 years ago

You stand on a frictionless platform that is rotating with an angular speed of 5.1 rev/s. Your arms are outstretched, and you ho

timurjin [86]

Answer:

$\omega'=19.419\ rev.s^{-1}$

Explanation:

Given:

angular speed of rotation of friction-less platform, $\omega=5.1\ rev.s^{-1}$

moment of inertia with extended weight, $I=9.9\ kg.m^2$

moment of inertia with contracted weight, $I'=2.6\ kg.m^2$

<u>Now we use the law of conservation of angular momentum:</u>

$I.\omega=I'.\omega'$

$9.9\times 5.1=2.6\times \omega'$

$\omega'=19.419\ rev.s^{-1}$

The angular speed becomes faster as the mass is contracted radially near to the axis of rotation.

5 0

3 years ago

To a nighttime observer on Earth, how many degrees do the stars appear to move around Polaris in 3 hours?

STatiana [176]

<span>The correct answer is 45 degrees. 360 degrees is 24 hours, because it takes a whole day for the earth to turn in one whole circle. So, to find how many degrees the stars seem to move per hour, simply divide the total number of degrees by the total number of hours in a day: 360/24 = 15. Since the question is asking how much the stars appear to move in 3 hours, now multiply the number of degrees per hour times 3: 15 x 3 = 45. </span>

5 0

3 years ago