Explanation:
First, we will calculate the total charge as follows.
= 
= 97.80 C
Now, we will calculate the current required by the jeweler to plate the bracelet as follows.
i = 
= 
= 
A
or, = 9.05 mA
thus, we can conclude that 9.05 mA current should he use to electroplate the bracelet in three hours.
Answer:
3.83×10¯⁴ N
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = +2.4x10¯⁸ C
Charge 2 (q₂) = +1.8x10¯⁶ C
Distance apart (r) = 1.008 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Force (F) =?
The magnitude of the electrical force acting between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
F = 9×10⁹ × 2.4x10¯⁸ × 1.8x10¯⁶ / (1.008)²
F = 0.0003888 / 1.016064
F = 3.83×10¯⁴ N
Thus the magnitude of the electrical force acting between the two charges is 3.83×10¯⁴ N
Answer:
A goal keepee catering the ball in time is answer
a clock .. and i guess a non functioning clock ?
