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Bezzdna [24]
3 years ago
5

Which is more likely to be dangerous-a volcano that erupts frequently or a volcano that has been inactive for a hundred years? W

hy?
Read More >>
Physics
2 answers:
Novosadov [1.4K]3 years ago
7 0

Answer:

The volcano that erupts frequently accumulates less lava (because it is being erupted frequently) so the eruptions are less massive and more controllable, but it's actually dangerous.

The other one, the inactive volcano is "safer" most of the time, the fact that it was active 100 years ago means that there is a possibility that it erupts in a given time, but with only this information you can't contemplate the actual danger of the eruption, it may be kinda small or cause a natural disaster.

So both of them are dangerous, the one that erupts frequently is most consistently dangerous, and the other has a probability of being really dangerous, but most of the time is not, then the right answer is:

"a volcano that erupts frequently"

Korvikt [17]3 years ago
6 0

Answer:

A volcano that erupts frequently.

Explanation:

Both.

But the volcano that hasn't erupted in 100 years would probably be more dangerous because you wouldn't be prepared for its explosion as you would be for the one that erupts frequently.

Glad I could help!!

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You performed an experiment in which you measured the amount of water leaking through differentiations types of roofs. For one r
natali 33 [55]
<h2>Hello!</h2>

The answer is: A. 4.5 L

<h2>Why?</h2>

According to the conversion factor which states that:

1gal=3.78L

It means that we have 3.78 L per each gallon or it's equal to say that we 0.26 gallon per each L.The SI unit for liquid volume is the Liter (L)

Let's make the calculations:

1.2 gal*\frac{3,78L}{1gal} =4,54 L

So, we have 4.54 L in 1,2 gallons.

Have a nice day!

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3 years ago
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4 years ago
How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 162 mL of coffee at 94.6°C so that the r
Andre45 [30]

Answer:

The volume of water is 139 mL.

Explanation:

Due to the Law of conservation of energy, the heat lost by coffee is equal to the heat gained by the water, that is, the sum of heats is equal to zero.

Q_{coffee} + Q_{water} = 0\\Q_{coffee} = - Q_{water}

The heat (Q) can be calculated using the following expression:

Q=c \times m \times \Delta T

where,

c is the specific heat of each substance

m is the mass of each substance

ΔT is the difference in temperature for each substance

The mass of coffee is:

162mL.\frac{0.997g}{mL} = 162g

Then,

Q_{coffee} = - Q_{water}\\c_{c} \times m_{c} \times \Delta T_{c} = -c_{w} \times m_{w} \times \Delta T_{w}\\m_{c} \times \Delta T_{c} = -m_{w} \times \Delta T_{w}\\m_{w} = \frac{m_{c} \times \Delta T_{c}}{-\Delta T_{w}} \\m_{w}=\frac{162g \times (62.5 \°C - 94.6 \°C ) }{-(62.5 \°C - 25.0 \°C)} \\m_{w} = 139 g

The volume of water is:

139g.\frac{1mL}{0.997g} =139mL

7 0
4 years ago
An undamped oscillator has period ro= 1.000 s, but I now add a little damping so that its period changes to r i= 1.001 s.
Firlakuza [10]

This Question has mistakes.Correct question is

An undamped oscillator has period  τo=1.000s , but I now add a little damping so that its period changes to  τ1=1.001s.

What is the damping factor β? By what factor will the amplitude of oscillation decrease after 10 cycles? Which effect of damping would be more noticeable, the change of period or the decrease of the amplitude?

Answer:

β=0.28 /sec

Amplitude=0.0606

Explanation:

T_{o}=2\pi  /w\\T_{1}=2\pi /\sqrt{w^{2} -\beta^{2}  }\\ As\\T_{o}=1 \\T_{1}=1.001\\From  T_{o}\\w=2\pi \\So\\T_{1}=w/\sqrt{w^{2} -\beta^{2}  }\\\beta =0.00447w\\\beta =0.00447(2\pi )\\\beta =0.28sec^{-1}\\ Amplitude=Ae^{-\beta t}\\ after\\ t=10T_{1}\\so\\Ae^{-\beta(10t_{1}) }=e^{-\beta(10t_{1}) }\\=e^{-\(0.28)(10)(1.001) }\\Amplitude=0.0606

7 0
4 years ago
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