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Bezzdna [24]
3 years ago
5

Which is more likely to be dangerous-a volcano that erupts frequently or a volcano that has been inactive for a hundred years? W

hy?
Read More >>
Physics
2 answers:
Novosadov [1.4K]3 years ago
7 0

Answer:

The volcano that erupts frequently accumulates less lava (because it is being erupted frequently) so the eruptions are less massive and more controllable, but it's actually dangerous.

The other one, the inactive volcano is "safer" most of the time, the fact that it was active 100 years ago means that there is a possibility that it erupts in a given time, but with only this information you can't contemplate the actual danger of the eruption, it may be kinda small or cause a natural disaster.

So both of them are dangerous, the one that erupts frequently is most consistently dangerous, and the other has a probability of being really dangerous, but most of the time is not, then the right answer is:

"a volcano that erupts frequently"

Korvikt [17]3 years ago
6 0

Answer:

A volcano that erupts frequently.

Explanation:

Both.

But the volcano that hasn't erupted in 100 years would probably be more dangerous because you wouldn't be prepared for its explosion as you would be for the one that erupts frequently.

Glad I could help!!

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A certain frictionless simple pendulum having a length L and mass M swings with period T. If both L and M are doubled, what is t
vampirchik [111]

The new period is D) √2 T

\texttt{ }

<h3>Further explanation</h3>

Let's recall Elastic Potential Energy and Period of Simple Pendulum formula as follows:

\boxed{E_p = \frac{1}{2}k x^2}

where:

<em>Ep = elastic potential energy ( J )</em>

<em>k = spring constant ( N/m )</em>

<em>x = spring extension ( compression ) ( m )</em>

\texttt{ }

\boxed{T = 2\pi \sqrt{ \frac{L}{g} }}

where:

<em>T = period of simple pendulum ( s )</em>

<em>L = length of pendulum ( m )</em>

<em>g = gravitational acceleration ( m/s² )</em>

Let us now tackle the problem!

\texttt{ }

<u>Given:</u>

initial length of pendulum = L₁ = L

initial mass = M₁ = M

final length of pendulum = L₂ = 2L

final mass = M₂ = 2M

initial period = T₁ = T

<u>Asked:</u>

final period = T₂ = ?

<u>Solution:</u>

T_1 : T_2 = 2\pi \sqrt{ \frac{L_1}{g} }} : 2\pi \sqrt{ \frac{L_2}{g} }}

T_1 : T_2 = \sqrt{L_1} : \sqrt{L_2}

T : T_2 = \sqrt{L} : \sqrt{2L}

T : T_2 = 1 : \sqrt{2}

\boxed {T_2 = \sqrt{2}\ T}

\texttt{ }

<h3>Learn more</h3>
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302
  • Young Modulus : brainly.com/question/9202964
  • Simple Harmonic Motion : brainly.com/question/12069840

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Elasticity

3 0
3 years ago
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Whenever you push an object across a frictional surface, it starts out taking a lot of force to push to get the object moving. H
son4ous [18]

Answer:

The answer is A

Explanation:

Here's an example. A child is in school taking a test. They have made a mistake on a question, and want to erase it. The eraser is made out of a type of rubber, the rubber has friction, which means the eraser has something that's going to resist movement. Now the child has exerted enough force to get it moving, and it's moving, it won't stop unless the child stops exerting force to keep it moving. Both Newton's 1st and 3rd law explain the action of moving something on a surface with friction.

5 0
3 years ago
Which of these is most likely to lead directly to a black market?
Sloan [31]
The answer is C.rationing.

<span>♡♡Hope I helped!!! :)♡♡
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7 0
3 years ago
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Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm .Part AAt a distance from the sl
77julia77 [94]

Answer:

The phase difference between waves 31.7 rad

Explanation:

Given :

Wavelength \lambda = 540 \times 10^{-9} m

Separation between two slit d = 0.370 \times 10^{-3} m

Angle \theta = 25°

From the formula of phase difference,

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Where \delta = phase difference

\delta = \frac{2 \times \pi \times 0.370 \times 10^{-3} }{540 \times 10^{-9} } \sin 25

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Therefore, the phase difference between waves 31.7 rad

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garik1379 [7]
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